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natta225 [31]
4 years ago
10

Largest factor of 5 and 15

Mathematics
2 answers:
rewona [7]4 years ago
5 0
The answer would be 5.

5- 5
15- 1, 3, 5, 15
harina [27]4 years ago
4 0
The largest factor of these two numbers is 5.
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Find the slope of the line that passes through these given points (-4,3) and (1,1)​
wel

Answer:

-2/5

Step-by-step explanation:

Slope is given by rise/run also known as y2-y1/x2-x1. --3 = -2, and 1 - (-4) = 5 hence -2/5.

3 0
3 years ago
A cat is running away from a dog at a speed of 3m/s. originally, the distance between them was 48 meters. What should be the spe
balandron [24]

Answer:

3.8\:\mathrm{m/s}

Step-by-step explanation:

Use the formula d=rt (distance is equal to rate/speed multiplied by time) to solve this problem.

We know that one minute is equal to 60 seconds. Therefore, the distance travelled by the cat in 1 minute is equal to d=3\cdot 60=180\text{ meters}.

To catch the cat, the dog needs to also cover an additional 48 meters, because the cat was initially 48 meters away from the dog and it ran away from the dog. Hence, the dog will need to cover 180+48=228 meters in one minute.

Therefore, we have:

228=60r,\\r=\frac{228}{60}=\boxed{3.8\:\mathrm{m/s}}

5 0
3 years ago
Read 2 more answers
IM GIVING 20 POINTS
Alla [95]

Answer:

you get 9/25

Step-by-step explanation:

formula for area of square

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plug in

3/5^2

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8 0
3 years ago
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4) Part A: A biologist counted the number of two types of salmon (Chanook and Steelhead) at a dam. He used the table below to re
sp2606 [1]

Answer:

The answer is 40

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8 0
3 years ago
The number of lightning strikes in a year at the top of a particular mountain has a poisson distribution with a mean of 3.8. fin
atroni [7]

Let X be the number of lightning strikes in a year at the top of particular mountain.

X follows Poisson distribution with mean μ = 3.8

We have to find here the probability that in randomly selected year the number of lightning strikes is 0

The Poisson probability is given by,

P(X=k) = \frac{e^{-mean} mean^{x}}{x!}

Here we have X=0, mean =3.8

Hence probability that X=0 is given by

P(X=0) = \frac{e^{-3.8} 3.8^{0}}{0!}

P(X=0) = \frac{0.02237 * 1}{1}

P(X=0) = 0.0224

The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224

5 0
4 years ago
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