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dsp73
2 years ago
8

Ack's Cafe is putting a new plastic cover over its outside menu shown below.

Mathematics
1 answer:
vekshin12 years ago
4 0

The area of the rectangular menu if the menu is 3 feet long by 2 feet wide is 6 square feet.

<h3>Area of a rectangle</h3>

  • Length of the rectangle = 3 feet
  • Width of the rectangle = 2 feet

Area of the rectangular menu = length × width

= 3 feet × 2 feet

= 6 square feet

Therefore, area of the rectangular menu if the menu is 3 feet long by 2 feet wide is 6 square feet.

Learn more about rectangle:

brainly.com/question/13048427

#SPJ1

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A confectionary company did a survey among students. It was found that 80 students liked pastries and 30 of those students liked
nikitadnepr [17]
90 is the answer..................
6 0
4 years ago
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Is (1,1) a solution the equation 2x - y = 1 ?​
stealth61 [152]

Answer:

Yes

Step-by-step explanation:

2 times 1= 2

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2-1=1

Yes

8 0
3 years ago
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1. Using the formula for the probability of one event or another event, calculate the probability of drawing a card from a stand
ddd [48]
A standard deck has 52 cards.
A standard deck has 4 jacks.
A standard deck has 13 clubs.

From this, we can derive the following:
The probability of drawing a jack is 4/52 or 1/13
The probability of drawing a club is 13/52 or 1/4

But since the problem asks for drawing jack or club, therefore we should add the 2 probabilities, making 17/52. This is not the final answer yet. We know that there is a jack of clubs, therefore we need to subtract 1 from the probabilities since jack of clubs were considered in the 2 categories of probability.

With that being said, the probability of drawing a club or a jack is 16/52 or 4/13

Bonus Question:

The first thing you need to do here is find the probability of each scenario. First let's do what is given, the probability of drawing 2 aces. Since there are 4 aces in a deck of 52, we can easily say that the probability of drawing an ace is 4/52. However for our second draw, the probability of drawing a different ace is 3/51. This is so since we already drew a card that is an ace, hence we need to subtract one from the total aces (4-1) and from the total cards in the deck (52-1). In getting the probability of drawing two aces, we need to multiply the said probabilities: 4/52 and 3/51, resulting to 1/221.

For the second scenario, the drawing of 2 red cards, we just use the same concept but in this, we are already considering the 2 red cards in the first scenario, therefore the chance of drawing a red on our first draw is 24/52. For our second, we just need to subtract one card, therefore 23/51. Multiply these two and we will get 46/221.

Now, the problem asks for the chance of drawing either 2 reds or 2 aces, therefore we add the probabilities of the 2 scenarios:
46/222 + 1/221 = 47/221

Summary:
First Scenario:
4/52 + 3/51 = 1/221
Second Scenario:
24/52 + 23/51 = 46/221
Chances of drawing 2 red cards or 2 aces:
1/221 + 46/221 = 47/221
7 0
3 years ago
Help me out question #9
Alex777 [14]
The original height of the plant is 20 inches, and each week for 4 weeks its height increases by 2h inches, so at the end of 4 weeks its height would be:
20 + 4(2h) = 20 + 8h
Now for the next two weeks the plant grows in height by h inches each week, so we need to add a further 2h inches to the equation. Thus the expression that shows the height of the plant after 6 weeks is:
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PLEASE ANSWER THIS QUESTION ACCURATELY
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Try 226.08. I'm pretty sure that's right.

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