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grigory [225]
2 years ago
15

Is (1,1) a solution the equation 2x - y = 1 ?​

Mathematics
2 answers:
stealth61 [152]2 years ago
8 0

Answer:

Yes

Step-by-step explanation:

2 times 1= 2

y=1

2-1=1

Yes

WINSTONCH [101]2 years ago
8 0

Answer:

Yes

Step-by-step explanation:

Substitute the x and y values into the equation.

2(1) - 1 = 1

2 - 1 = 1

1 = 1

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Plz help I'll give brainlest
jarptica [38.1K]
<h3>1.Area of the parallelogram= 288 square units</h3><h3>2.Area of the parallelogram=45 m^2</h3><h3>3.Area of the trapezoid   = 34 square in.</h3><h3>4.Area of the trapezoid = 8 square ft</h3><h3>5.Area of the rhombus= 27 square cm</h3><h3>6.Area of the rhombus= 108 square in</h3><h3>7.The area of the desktop is  = 1200 square in</h3><h3>8.The area of the rhombus is =84 cm^2</h3><h3>9.Area of the trapezoid  = 240 square ft</h3>

Step-by-step explanation:

1.

Base =16 ft and Height = 18 ft

Area of the parallelogram = base × height

                                       =16× 18 square units

                                       = 288 square units

2.

Base = 9 m and height = 5 m

Area of the parallelogram = base × height

                                        =(9×5) m^2

                                         =45 m^2

3 .

Height = 4 in and parallel sides are 12 in and 5 in

Area of the  trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                            =\frac{1}{2} \times (12+5) \times 4 square in.

                             = 34 square in.

4.

Height = 2 ft  and parallel sides are 2 ft and 6 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                              =\frac{1}{2} \times (2+6) \times 2 square ft

                              = 8 square ft

5.

Diagonals are 6 cm and 9 cm.

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 6\times 9 square cm

                               = 27 square cm

6. Diagonals are 12 in and 18 in

Area of the rhombus = \frac{1}{2}\times {\textrm{product of diagonals}

                               =\frac{1}{2 } \times 12\times 18 square in

                               = 108 square in

7. Given a desktop in the shape of a parallelogram has a base 30 in. and a height of 40 in

The area of the desktop is = (30 × 40 ) square in

                                            = 1200 square in

8. Given , a rhombus has one diagonal that is 14 cm and other diagonal 12 cm.

The area of the rhombus = \frac {1}{2} \times 14 \times 12 cm^2

                                         =84 cm^2

9.Given , the base of trapezoid are 24 ft  and 16 ft and height is 12 ft

Area of the trapezoid =\frac {1}{2} \times( {\textrm{sum of the parallel sides}}) \times height

                                    = \frac{1}{2} \times (24+16) \times 12 square ft

                                     = 240 square ft

8 0
3 years ago
Solve the problem . (x – 2) = –14(x – 8)<br> 1) x=0<br> 2)x=--5 1/3<br> 3)x=-3 1/5<br> 4)x=3 1/5
Mrrafil [7]

Answer:

x=38/5

Step-by-step explanation:

distribute

Add 2 to both sides of the equation

Simplify

8 0
2 years ago
Is there a proportional relationship? A salt water solution for and aquarium calls for 35 parts of salt to 1000 parts of water t
morpeh [17]

Answer:

Yes

Step-by-step explanation:

To check proportionality :

35 α 1000

35 = 1000k

k = constant of proportionality ;

Divide both sides by 1000 to obtain k

35 / 1000 = 1000k / 1000

0.035 = k

For the ratio Given :

Ratio of 7 parts of salt and 200 parts of water

7 : 200

7 / 200

= 0.035

Since,

k = 0.035 ; 7 / 200 = 0.035

Hence, a proportional relationship exists.

7 0
2 years ago
A triangle has an area of 75 feet, with a base of 10 feet. What is the height?
densk [106]

Answer:

its 85 feet :)

8 0
2 years ago
Factor 24x-40 using GCF
posledela

Answer:

8(3x-5)

8 is the GCF of 24 and 40 so you write 8 and in brackets you put your terms after you divide by 8 so you get 3x and -5 so it is written as 8(3x-5)

3 0
3 years ago
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