To find the area of the larger figure, let's multiply the length by the width.
9 ft * 4 ft = 36ft^2
Let's do the same thing with the smaller figure.
3 ft * 4 ft = 12ft^2
Let's add the area of both figures together.
36ft^2 + 12ft^2 = 48ft^2
Let the width of the rectangle be 'w'
According to the question length of the rectangle (l) is three feet more than twice it's width;
l = (2w + 3) ft
Perimeter of rectangle = 78 ft
Formula of perimeter of rectangle = 2(Length + Width)
So,

Width of the rectangle (w) = 12 ft
Answer:
Exponential
Step-by-step explanation:
Ir's exponential because linear would mean it is increasing by a specific number every year, in which this case does not. Quadratic would mean a vertex form would need to be used, and with the information given , that could not happen.
Answer:
A. (2, -3).
Step-by-step explanation:
The first step is to complete the square on the terms in x and the terms in y:
x² - 4x +4 +y² +6y + 9 =4
= (x - 2)² - 4 + (y + 3)² - 9 + 4 + 9 = 4
= = (x - 2)² + (y + 3)² - 9 + 9 - 4 + 4 = 4
= (x - 2)² - (y + 3)² = 4.
So the centre is at (2, -3).