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xxTIMURxx [149]
4 years ago
14

Can you help me find out what c is?

Mathematics
1 answer:
attashe74 [19]4 years ago
7 0

Answer:  "  z = 10^(^3^m^-^2^n^)  " .

________________________________

Step-by-step explanation:

________________________________

The question states:  "<em><u>Can [you] help [me] find out what </u></em><u>"c"</u><em><u> is</u></em> ? " .

________

       "Can [you] help [me] find out what "c" is ? " .

 →  We are to answer: "Part C" —within the "attached image" given:

________

 →   " 1000^m ÷ 100^n " ;  can be written in the form of:  " 10^z " .

 →     Express <em>z</em>  in terms of <em>m</em> and<em> n</em> .

________

<u>Note</u>: Rewrite:  " 1000^m " ;   and:  " 100^n " ;   as powers of "10" ;

  →  with "10" being the "base number" .

________

Let us start with:  " 1000^m " .

Note that the number:  " 1000 = 10^3 " ;

     →   since " 1000 " ;  has 3 (three) zeros after the "1" digit;

     → & since:  " 10^3 = 10 * 10* 10 = 1000 " .

So:  →   1000^m = (10^3)^m .

Now, let's simplify further.

Note the "multiplication property" of exponents:

    →  (a^b)^c = a^(^b^*^c^)=a^(^b^c^) .

As such:  →   1000^m=(10^3)^m = 10^(^3^*^m)=10^(^3^m^) .

________

Likewise:  We can continue by rewriting our other term:

    →  " 100^n " ;  as a power of "10" ;

             with "10" being the "base number."

Note that the number:  " 100 = 10^2 " ;

     →   since " 100 " ;  has 2 (two) zeros after the "1" digit;

     →  & since:  " 10^2 = 10 * 10 = 100 " .

So:

     →   100^n = (10^2)^n .

Now, let's simplify further.

________

Again:  As aforementioned:

Note the "multiplication property" of exponents:

    →  (a^b)^c = a^(^b^*^c^)=a^(^b^c^) .

As such:

     →  100^n = (10^2)^n=10^(^2^*^n^) = 10^(^2^n^) .

________

Now, refer to the original problem:

     →  " 1000^m  ÷  100^n  "  ;  

Rewrite this expression by substituting:

    →   " 10^(^3^m^) " ;  ←  [for:  " 1000^m ."] ;  And:

    →   " 10^(^2^n^) " ;   ←  [for:  " 100^n ."] ;

As follows:

    →  " 10^(^3^m^)  ÷  10^(^2^n^) "  .

________

Now:  Note the following "division property" of exponents:

________

    →  \frac{a^m}{a^n} = a^(^m^-^n^) ;  a\neq 0 .

________

As such; let's rewrite our expression; and simplify—by plugging in our values into the "equation/formula" directly above; in which:

________

→  " a " [in the aforementioned formula] is:   " 10 " .

→  " m " [the 'exponent' in the aforementioned formula] is:                                                                                                    

                                                                          " (3m) " .

→  " n " [the 'exponent' in the aforementioned formula is:

                                                                          " (2n) " .

→  " a^m " [in the aforementioned formula] is:  " 10^(^3^m^) " ;

→  " a^n "  [in the aforementioned formula] is:  " 10^(^2^n^) " .

________

  →  Let's plug in our values;  and then "simplify" ; as follows:

________

→   \frac{10^(^3^m^)}{10^(^2^n^)} = ? ;  

               = 10^(^3^m^-^2^n^) .

→   \frac{10^(^3^m^)}{10^(^2^n^)} = 10^(^3^m^-^2^n^)    .

________

So:  →   " 10^z = ? " ;

    ↔   " 10^z = 10^(^3^m^-^2^n^) " .

         →  " z = 10^(^3^m^-^2^n^) " .

_______________________________________

Hope this answer is helpful.

  Best wishes to you in your academic endeavors

          —and within the "Brainly" community!

_______________________________________

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