ANSWER
0.756
EXPLANATION
Let x represent number of correct answers.
We can find
which leads us to
which uses the compliment of 
to find the probability of getting at least 2 questions correct.
Note that since 
and 
are mutually exclusive, we have
Then 
as we have 
to answer the questions incorrectly divided by the total 
to answer the questions.
Exactly 1 answer correct: 
Therefore
![\begin{aligned} P(x \ge 2) &= 1 - P(x = 0\text{ or }x =1) \\ &=1 - \big[P(x=0) + P(x=1)\big] \\ &=1 - \left[ (3/4)^{10} + {}_{10}C_1 \cdot (3/4)^9(1/4)^1 \right] \\ &\approx 0.756 \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%0AP%28x%20%5Cge%202%29%20%26%3D%201%20-%20P%28x%20%3D%200%5Ctext%7B%20or%20%7Dx%20%3D1%29%20%5C%5C%0A%26%3D1%20-%20%5Cbig%5BP%28x%3D0%29%20%2B%20P%28x%3D1%29%5Cbig%5D%20%5C%5C%0A%26%3D1%20-%20%5Cleft%5B%20%283%2F4%29%5E%7B10%7D%20%2B%20%7B%7D_%7B10%7DC_1%20%5Ccdot%20%283%2F4%29%5E9%281%2F4%29%5E1%20%5Cright%5D%20%5C%5C%0A%26%5Capprox%200.756%0A%5Cend%7Baligned%7D%20)
X=number of senior tickets
y=number of student tickets
1st day
7x+1y=101
2nd day
7x+12y=134
easy, we can eliminate the x's
multiply first equation by -1
-7x-1y=-101
<u>7x+12y=134 +</u>
0x+11y=33
11y=33
divide by 11 both sides
y=3
sub back
7x+y=101
7x+3=101
minus 3 both sides
7x=98
divide both sides by 7
x=14
senior tickets cost $14
student tickets cost $3
that sounds unfair
The sum of 5+2=7
The sum of 2+5=7
The sum is the same because basically, the position and location of the numbers do not matter in <em>addition </em>and multiplication. However, the position matters in subtraction and division.
Hope that helps!
Answer:
x = 
Step-by-step explanation:
I would subtract 5x and 2 on both sides to get x^2 - 5x - 2 = 0, and using the A = 0, B = -5, and C = -2 to plug it into the quadratic equation which is
*Ignore the A please I cannot get rid of it.*
