All categories

3 years ago

How do you determine each of the two expressions of the equation when the mathematical statement is given in words?

Mathematics

1 answer:

Lyrx [107]3 years ago

8 0

Answer:

The solution of an equation is the value that when substituted for the variable makes the equation a true statement. To achieve our goal, we use two principles of equality, the addition principle and the multiplication principle.

Step-by-step explanation:

You might be interested in

( PLEASE HELP ) <br><br> What is the solution to the inequality below?

Lunna [17]

Answer:

Step-by-step explanation:

You are to take the square root across the inequality sign to make it plus or minus 3 squared.

The answer will therefore be C

5 0

3 years ago

Find the missing angle<br>PLZ HELP

Nadusha1986 [10]

Answer:

The answer is 94 degrees.

Step-by-step explanation:

The total number of degrees in a triangle is 180.

So you would subtract 35 and 51 from 180.

180-35-51=94

Hope this helps <3

6 0

3 years ago

The frequency distribution representing the number of frequent flier miles accumulated by employees at Brumley Statistical Consu

alisha [4.7K]

Answer:

a. How many employees accumulated less than 3,000 miles?

The number of employees accumulated less than 3,000 miles= 5

So the number of employees accumulated less than 3,000 miles is 5.

d. Based on the cumulative frequency polygon, about 75% of the employees accumulated how many miles or less?

8.5 thousands of miles, found by starting at 75 percent on the vertical axis on the right, over to the polygon and then down to the horizontal axis.

Step-by-step explanation:

The given frequency distribution representing the number of frequent flier miles accumulated by the employees in a company.

Frequent Flier Miles (000) Frequency

0 up to 3 5

3 up to 6 12

6 up to 9 23

9 up to 12 8

12 up to 15 2

Total 50

a. How many employees accumulated less than 3,000 miles?

The number of employees accumulated less than 3,000 miles= 5

So the number of employees accumulated less than 3,000 miles is 5.

b. Convert the frequency distribution to a cumulative frequency distribution.

We make the cumulative frequency distribution from the frequency distribution by adding up a frequency and all other frequencies below it.

Frequent Flier Miles Frequency Cumulative frequency

0 up to 3 5 5

3 up to 6 12 17

6 up to 9 23 40

9 up to 12 8 48

12 up to 15 2 50

Total 50

d. Based on the cumulative frequency polygon, about 75% of the employees accumulated how many miles or less?

8.5 thousands of miles, found by starting at 75 percent on the vertical axis on the right, over to the polygon and then down to the horizontal axis.

8 0

3 years ago

Can you help me with #6??<br>(Algebra 1 sucks..)

Lina20 [59]

Answer:

Step-by-step explanation:

Use the given functions to set up and simplify

6 0

3 years ago

A government report gives a 99% confidence interval for the proportion of welfare recipients who have been receiving welfare ben

juin [17]

Answer:

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

The estimation for the proportion for this case is $\hat p = 0.21$

And we know that the 99% confidence interval is given by:

$0.21 \pm 0.045$

So then the margin of error at 99% of confidence is 0.045, and the margin of error is given by this formula:

$ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

If we decrease the confidence level this margin of error can't be higher than 0.045 so then the correct answer for this case would be:

d. 21% ± 4.8%

Because if the z value decrease from 2.58 to 1.96 not makes sense that the margin of error increase from 0.045(4.5%) to 0.048(4.8%)

5 0

3 years ago