Answer:
BX will hold 6444 in hex format.
Explanation:
From the given information:
We need to understand that AX is 64-bit hex number.
When performing ASM instruction (Assembly language instruction),
The addition of 2111 + 4333 = 6444 will be in BX.
This is because ADD, BX, AX will add bx and ax; and the final outcome will be stored in BX.
∴
BX will hold 6444 in hex format.
Answer:
II and III
Explanation:
In the snippets of code provided the only ones that will evaluate to true will be conditions II and III. Condition one has and (&&) comparisons meaning that every single condition needs to be true in order for the overall condition to be true, if only two variables are guaranteed to be equal then the third variable could be different which would ultimately evaluate to false. Condition 2 has or (||) comparison meaning only one needs to be true in order for the overall condition to be true and since we are already told that at least two are equal then it will always evaluate as true. Condition 3 is an arithmetic problem that will always equal 0 because two of the variables are equal, meaning that when they subtract it will give 0, and anything multiplied by 0 will equal 0 as well. Therefore, evaluating to true.
What is output by the code below? int[] array = {33,14,37,11,27,4,6,2,6,7}; System .out.println(array.length); ... int[] array = {5,10,3,6,9,15}; ... int total = 0; ... output by the code below? int j=1, tally=0; while(j<9) { tally++; j++; } System.out.print(tally);.
From quizlet
<span>A touch screen gives response and acts simply with a touch on the screen area. Reflective screen is not a basic type of touch screen. The reflection can be reduced for the touch screen when it is combined with the LCD and the screen still be very visible. These screens can be anti glare and safe to the eyes.</span>
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