Answer:
-2
Step-by-step explanation:
Just use 6-8 and you will get - 2
Check again with - 2+8 you will get positive 6
Quadratic equation which has no solution gives zero for the value of d.
d = b² - 4ac
0 = 3² +- 4(-1)c
-9 = +_ 4c
c = -9/-4 pr 9/-4
c = 9/4 or -9/4
In short, Your Answers would be Option C & E
Hope this helps!
Take the homogeneous part and find the roots to the characteristic equation:

This means the characteristic solution is

.
Since the characteristic solution already contains both functions on the RHS of the ODE, you could try finding a solution via the method of undetermined coefficients of the form

. Finding the second derivative involves quite a few applications of the product rule, so I'll resort to a different method via variation of parameters.
With

and

, you're looking for a particular solution of the form

. The functions

satisfy


where

is the Wronskian determinant of the two characteristic solutions.

So you have




So you end up with a solution

but since

is already accounted for in the characteristic solution, the particular solution is then

so that the general solution is
Answer:
3sqrt(2) ................
Answer:
Option 4 is the image of the given figure.
Step-by-step explanation:
We are given that,
The shape EFGHCD is transformed to form another shape.
From the options, we see that,
Figure 2 and 3 does not have the same vertices as that of the figure.
So, they are discarded.
Since, after transforming a figure, we get a new figure.
So, the vertices cannot have same name as that of the original figure.
So, option 1 is discarded.
Thus, we get,
Option 4 is the image of the given figure after transformation as shown below.