Question

Find the first 5 terms given the nth term.

Answer 1

Answer:

• -2,4,-8,16,-32

Step-by-step explanation:

let's understanding the question situation,

we have to find the first 5 terms given the nth term.

According to the question,

The given term is

$\\ \qquad \qquad \large \boxed{ \sf{ \: \: a_n = (- 2)^n \: \: }}$

Solution:-

• ${ \sf{ \: \: a_{1} = (- 2)^{1}=\bold{-2} \: \: }}$

• ${ \sf{ \: \: a_{2} = (- 2)^{2}=\bold{4} \: \: }}$

• ${ \sf{ \: \: a_{3} = (- 2)^{3}=\bold{-8} \: \: }}$

• ${ \sf{ \: \: a_{4} = (- 2)^{4}=\bold{16} \: \: }}$

• ${ \sf{ \: \: a_{5} = (- 2)^{5}=\bold{-32} \: \: }}$

Final answer:-

.°. The First 5term is -2,4,-8,16,-32.

Answer 2

Answer:

-2, 4, -8, 16, -32, ...

Step-by-step explanation:

To find any term given the nth term, simply substitute the value of n into the given nth term equation.

Given nth term equation:

$\large \boxed{\rm a_n=(-2)^n}$

Therefore, to find the first 5 terms, substitute the values of n of 1 through 5 into the nth term equation, remembering to apply the following exponent rules:

  $\rm (-a)^n=-a^n, \quad \textsf{if }n \textsf{ is odd}$

  $\rm (-a)^n=a^n, \quad \textsf{if }n \textsf{ is even}$

First 5 terms

$\rm a_1=(-2)^1=-2$

$\rm a_2=(-2)^2=4$

$\rm a_3=(-2)^3=-8$

$\rm a_4=(-2)^4=16$

$\rm a_5=(-2)^5=-32$