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Bad White [126]
3 years ago
13

Factorise :12(x²+7)²-8(x²+7)(2x-1)-15(2x-1)²

Mathematics
2 answers:
Readme [11.4K]3 years ago
7 0
12(x^2+7)2−8(x^2+7)(2x−1)−15(2x−1)^2

Distribute:

=12x^4+168x^2+588+−16x^3+8x^2+−112x+56+−60x^2+60x+−15

Combine Like Terms:

=12x^4+168x^2+588+−16x^3+8x^2+−112x+56+−60x^2+60x+−15

=(12x^4)+(−16x^3)+(168x^2+8x^2+−60x^2)+(−112x+60x)+(588+56+−15)

=12x^4+−16x^3+116x^2+−52x+629

adelina 88 [10]3 years ago
3 0
12(x²+7)²-8(x²+7)(2x-1)-15(2x-1)²

(x²+7)=a
(2x-1)=b

12a²-8ab-15b²=12a²-18ab+10ab-15b²=6a(2a-3b)+5b(2a-3b)=(2a-3b)(6a+5b)

[ 2(x²+7)-3(2x-1) ] [ 6(x²+7)+5(2x-1) ]=
( 2x²+14-6x+3 ) ( 6x²+42+10x-5) )=
(2x²-6x+17)(6x²+10x+37)=
2x²×6x² -  6x × 6x² +17×6x² + 2x²×10x - 6x ×10x+17×10x+2x²×37-6x ×37+17 × 37=
12x⁴ -36x³+102x²+20x³-60x²+170x+74x²-222x+629=
12x⁴ -36x³+20x³+102x²-60x²+74x²+170x-222x+629=
<u>=12x⁴-16x³+116x²-52x+629</u>
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<u>Step-by-step explanation:</u>

First, eliminate one of the variables and solve for the remaining variable:

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Next, replace "y" with -2 into either of the original equations to solve for x:

2x - 5y = 2

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 x          = -4

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<u>Check:</u>

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(Option 2)

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