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3 years ago

5

For what values of x is the following equation satisfied : 3x+9 = 21+7x ?

2 answers:

olya-2409 [2.1K]3 years ago

4 0

First of all, the first power of 'x' is the highest power in the whole equation,
so we only expect one solution.

You said that <span><u>3x+9 = 21+7x </u>

Subtract 3x from each side:

9 = 21 + 4x

Subtract 21 from each side:

-12 = 4x

Divide each side by 4 :

<u>-3 = x </u>
</span>

algol [13]3 years ago

4 0

$3x+9 = 21+7x\\
4x=-12\\
x=-3$

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The quantity q varies inversely with the square of m and directly with the product of r and x. When q is 2.5, mis 4 and the

saveliy_v [14]

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7 0

3 years ago

Read 2 more answers

Fraction simplifier de <img src="https://tex.z-dn.net/?f=%5Cfrac%7B15%7D%7B35%7D" id="TexFormula1" title="\frac{15}{35}" alt="\f

Pavel [41]

You have to divide them with 5
3/7

3 0

3 years ago

The price of a certain computer stock t days after it is issued for sale is p(t)=100+20t−6t^2 dollars. The price of the stock in

Elanso [62]

Answer:

0 < t < $\frac{5}{3}$

After 1.67 days the stocks would be sold out.

Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

p(t) = 100 + 20t - 6t²

Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = $\frac{20}{12}$

t = $\frac{5}{3}$ days

Therefore, there are two intervals in which the given function is defined

(0, $\frac{5}{3}$ ) and ( $\frac{5}{3}$ , ∞)

For the interval (0, $\frac{5}{3}$ ),

p'(1) = 20 - 12(1) = 20

For the interval ( $\frac{5}{3}$ , ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, $\frac{5}{3}$ ) indicates that the function is increasing.

0 < t < $\frac{5}{3}$

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

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3 years ago