Answer : 2/4 children will have earlobes that are not attached
The solution of the inequality is -8 ≥ b, and the correct graph is the one in option D.
"number line with a closed circle plotted at negative eight and arrow pointing left."
<h3>
How to solve the inequality?</h3>
Here we have the inequality:
-0.8*b + 2.3 ≥ 8.7
And we want to solve this, to do so, we need to isolate the variable b in one of the sides of the inequality.
-0.8*b + 2.3 ≥ 8.7
2.3 - 8.7 ≥ 0.8*b
-6.4 ≥ 0.8*b
-6.4/0.8 ≥ b
-8 ≥ b
So the solution is the set of all numbers equal to or smaller than -8, then the correct graph will be the one described by D.
Learn more about inequalities:
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Answer:
n = P/8.75
Step-by-step explanation:
Jose’s pay (P) depends on the number (n) of hours he works.
P = 8.75n Divide both sides by 8.75
n = P/8.75
=====
P = $61.25
n = 61.25/8.75
n = 7 h
Jose worked for 7 h.
Answer:
yes
Step-by-step explanation:
yes
R=(3V4<span>Home: Kyle's ConverterKyle's CalculatorsKyle's Conversion Blog</span>Volume of a Sphere CalculatorReturn to List of Free Calculators<span><span>Sphere VolumeFor Finding Volume of a SphereResult:
523.599</span><span>radius (r)units</span><span>decimals<span> -3 -2 -1 0 1 2 3 4 5 6 7 8 9 </span></span><span>A sphere with a radius of 5 units has a volume of 523.599 cubed units.This calculator and more easy to use calculators waiting at www.KylesCalculators.com</span></span> Calculating the Volume of a Sphere:
Volume (denoted 'V') of a sphere with a known radius (denoted 'r') can be calculated using the formula below:
V = 4/3(PI*r3)
In plain english the volume of a sphere can be calculated by taking four-thirds of the product of radius (r) cubed and PI.
You can approximated PI using: 3.14159. If the number you are given for the radius does not have a lot of digits you may use a shorter approximation. If the radius you are given has a lot of digits then you may need to use a longer approximation.
Here is a step-by-step case that illustrates how to find the volume of a sphere with a radius of 5 meters. We'll u
π)⅓