694
you just subtract 1212 by 518
694+518=1212
The attached should help you
the distance form X to Y is clearly -6 to 0 is 6 units, and 0 to 8 is 8 units, so 6 + 8 = 14 units.
now, for XZ and ZY we can simply use as stated, the distance formula to get those and then add them all to get the perimeter.
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ X(\stackrel{x_1}{-6}~,~\stackrel{y_1}{2})\qquad Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ XZ=\sqrt{[5-(-6)]^2+[8-2]^2}\implies XZ=\sqrt{(5+6)^2+(8-2)^2} \\\\\\ XZ=\sqrt{121+36}\implies \boxed{XZ=\sqrt{157}} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20X%28%5Cstackrel%7Bx_1%7D%7B-6%7D~%2C~%5Cstackrel%7By_1%7D%7B2%7D%29%5Cqquad%20Z%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B8%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20XZ%3D%5Csqrt%7B%5B5-%28-6%29%5D%5E2%2B%5B8-2%5D%5E2%7D%5Cimplies%20XZ%3D%5Csqrt%7B%285%2B6%29%5E2%2B%288-2%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20XZ%3D%5Csqrt%7B121%2B36%7D%5Cimplies%20%5Cboxed%7BXZ%3D%5Csqrt%7B157%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ Z(\stackrel{x_2}{5}~,~\stackrel{y_2}{8})\qquad Y(\stackrel{x_2}{8}~,~\stackrel{y_2}{2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ ZY=\sqrt{(8-5)^2+(2-8)^2}\implies ZY=\sqrt{9+36}\implies \boxed{ZY=\sqrt{45}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{perimeter}{14+\sqrt{157}+\sqrt{45}}\qquad \approx \qquad 33.2](https://tex.z-dn.net/?f=%5Cbf%20~~~~~~~~~~~~%5Ctextit%7Bdistance%20between%202%20points%7D%20%5C%5C%5C%5C%20Z%28%5Cstackrel%7Bx_2%7D%7B5%7D~%2C~%5Cstackrel%7By_2%7D%7B8%7D%29%5Cqquad%20Y%28%5Cstackrel%7Bx_2%7D%7B8%7D~%2C~%5Cstackrel%7By_2%7D%7B2%7D%29%5Cqquad%20%5Cqquad%20d%20%3D%20%5Csqrt%7B%28%20x_2-%20x_1%29%5E2%20%2B%20%28%20y_2-%20y_1%29%5E2%7D%20%5C%5C%5C%5C%5C%5C%20ZY%3D%5Csqrt%7B%288-5%29%5E2%2B%282-8%29%5E2%7D%5Cimplies%20ZY%3D%5Csqrt%7B9%2B36%7D%5Cimplies%20%5Cboxed%7BZY%3D%5Csqrt%7B45%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7Bperimeter%7D%7B14%2B%5Csqrt%7B157%7D%2B%5Csqrt%7B45%7D%7D%5Cqquad%20%5Capprox%20%5Cqquad%2033.2)
For the first question, the answer is 25/14.
Because 14x = 25y Which means x must equal more than y. And 25/14 is the only answer like this.
For the second question, the answer is 30 x 18.
30/5 = 6 18/3 = 6 18 + 18 + 30 + 30 = 96
So, both the perimeter and the ratio is correct with this answer.
For the third question, the first answer is correct.
x < -4 and only a negative number can be less than another negative. Also, the negative must have a higher value to be less than another negative.
For the last question, the last answer is correct. no explanation for this one, it would take too long ;)
Given:
and
.
To find:
The quadrant.
Solution:
We know that,
In I quadrant, all trigonometric ratios are positive.
In II quadrant, only
are positive and others are negative.
In III quadrant, only
are positive and others are negative.
In IV quadrant, only
are positive and others are negative.
We have,
and
.
Here,
is positive and
is negative. So,
lies in the III quadrant.
Therefore, the correct option is C, i.e., III.