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Vladimir79 [104]
2 years ago
9

Look at photo (10 points)

Mathematics
2 answers:
Lady_Fox [76]2 years ago
8 0

m perpendicular to q is the correct answer

borishaifa [10]2 years ago
6 0

Answer:

A, C and D

they all connect at a right angle. it is not b because p and q are parallel.

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Solve for b. <br><br> 3-2(b-2)=2-7b<br><br>PLEASE ANSWER QUICKLY!
Rufina [12.5K]
3b-6-2b+4=2-7b
b-2=2-7b
8b=4
b=4/8
b=1/2

Hope this helps.
5 0
3 years ago
Read 2 more answers
Find the function y = f(t) passing through the point (0,12)
Akimi4 [234]
Y=t+12 this is one the answers
7 0
3 years ago
Name
Tpy6a [65]

Answer:

1. A container of milk 2L

2. An Eyedropper has 1 mL

3. A cup of punch 250 mL

4. A jar of pickles 500mL

Step-by-step explanation:

Without even measuring, just think of this problem logically. Remember that a 1 L is 1000mL, so it is 1000 times more than 1 mL.

A milk container would hold more than a cup of milk and that is more than 20 mL. The most logical answer would be 2L.

An eyedropper can hold just a little amount of liquid. Just think that it dispenses liquid in drops, the best answer would be 1mL (which is actually an estimate of the volume of a drop is.)

A cup of punch is about 250 mL. The keyword there is a CUP and 25L is a big amount and the cup would have to be HUGE.

Same as above, the keyword there is a jar. A 50L jar would be a very big amount for just a jar of pickles.

8 0
3 years ago
A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in
Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

\frac{dr}{dt} =\frac{1}{2} --- rate of the radius

\frac{dh}{dt} =-\frac{1}{3} --- rate of the height

r = 2

h = \frac{1}{3}

Required

Determine the rate of change of the cone volume

The volume of a cone is:

V = \frac{\pi}{3}r^2h

Differentiate with respect to time (t)

\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})

Substitute values for the known variables

\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))

\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)

\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}

\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}

\frac{dV}{dt} = -\frac{88}{63}

\frac{dV}{dt} =-1.396in^3/min

The volume is decreasing at the rate of 1.396 cubic inches per minute

3 0
3 years ago
What is the best estimate of the area of the figure if each square has a side length of 1 mm?
Tanya [424]

29 square inches

Step-by-step explanation:

5 x 5 = 25

Triangles = 0.5

25 + 2 = 27

27 + (4 x 0.5)

27 + 2 =29

6 0
3 years ago
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