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Dennis_Churaev [7]
1 year ago
12

In lines 40-43 ("Moonless . . . Sun"), the narrator’s

Mathematics
1 answer:
aleksley [76]1 year ago
6 0

(C) "symmetry"

When the planetarium display reveals that Mercury's orbit is more difficult than previously believed, the narrator is dismayed. Contrary to the antiquated notion that Mercury rotates simply once every solar orbit, it appears that the moonless planet rotates three times per two trips around the sun. The narrator seems to favor "symmetry," or balance, by favoring the more straightforward "arrangement."

The answer is not (A). Lines 40–43 don't show any "irony" on the part of the narrator. (B) is the wrong answer. Though unconventional, the narrator's response to Mercury's "strange arrangement" does not truly show "inventiveness" or ingenuity. The answer is not (D). The passage's narrator gives a lot of facts, yet he does it in an understandable way.

Therefore, it is a little misleading to say that the narrator's manner in lines 40–43 is decorative or ornamented. The answer is not (E). Regarding Mercury's complex orbit, the narrator seems to dislike "ambiguity" or confusion rather than enjoy it.

Here's another question with an answer similar to this about passage analysis: brainly.com/question/3521530

#SPJ4

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Answer:

p = - 4

Step-by-step explanation:

Calculate the slope m using the slope formula and equate to - 4

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 3, p ) and (x₂, y₂ ) = (- 4, 0 )

m = \frac{0-p}{-4-(-3)} = \frac{-p}{-4+3} = \frac{-p}{-1} = p = - 4

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3 years ago
What is the sound level for a noise that has an intensity of 9.9 × 10-5 watts/m2?
horsena [70]

Given: Sound Intensity ( I ) = 9.9 \times  10^{-5}\frac{watts}{m^2}

We know,  the approximate threshold of human hearing is at 1kHz. In watts/m^2 it's value is =\frac{9.9 \times  10^{-5}}{10^{-12}}⁻¹² W/m².

So, we can say,  Reference sound intensity(I_0) = 10⁻¹² W/m².

We have formula for "sound intensity level LI in dB" when entering sound intensity.

LI = 10×log (I / Io)  in dB

Plugging values of I and Io in formula.

LI = 10 × log (\frac{9.9 \times  10^{-5}}{10^{-12}})

LI = 10 × log (99000000)

= 10 × 7.99564

LI = 79.96 dB.

Therefore,  79.96 dB is the sound level for a noise that has an intensity of 9.9 × 10-5 watts/m2.

8 0
3 years ago
I need help fast please!!!!!
Inessa05 [86]

Answer:

255.7 cm²

Step-by-step explanation:

A = 10²(3.14) = 314

(293/360)(314) = 255.7 cm²

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Answer:

she would need 60 more inches

Step-by-step explanation:

4feet =1 yard

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1 1/2 pinyt

Step-by-step explanation:

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