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3 years ago

4. Four friends went on a trip to Mexico. They rented a car for eight days which cost

Mathematics

1 answer:

nlexa [21]3 years ago

3 0

Explanation:

So, I know a lot of people won't do it this way, but this is how I would do it.

First, multiply each expense by eight (eight for the eight days)

$55 x 8 = 440

$25 x 8 = 200

$129 x 8 = 1032

Next, take the three answers and add them together:

440 + 200 + 1032 = 1672

Lastly, divide 1672 by four (four for the four friends)

1672/4 = 418

There you go! Here is your answer. Each friend paid $418

Hope I helped! :D

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Find two consecutive whole numbers that square root 105 lies between

tatiyna

When you are finding 2 consecutive numbers that a square root falls between, you have to think about what the closest whole numbers are, for example, if you have the sq root of 17, it would fall between 4² (16) and 5² (25).

So, in this case, √105 would fall between 10² (100) and 11² (121)

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4 years ago

A glacier receded 4 feet a day for a period of 25 days how much shorter was the glacier at the end of the period

KonstantinChe [14]

4*25=100

The glacier was 100 feet shorter than it was originally by the end of the 25 day period.

Hope this helps :)

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3 years ago

You have $15 to spend in a candy store. If Kitkat cost $0.75 each and mini Snickers are $0.25 each.

zhuklara [117]

Answer:

1. 60 snickers

2. 20 KitKats

i cannot anwser 3 cause its not showing up somehow. Sorry.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Unit 3, Lesson 7

aksik [14]

Answer:

Find the complete table in attached file.

Step-by-step explanation:

Find the Incomplete table in attached file

Given:

A car travels 55 miles per hour for 2 hours.

So the speed of the car 55 miles per hour is constant for 2 hours.

Using speed formula.

$Speed=\frac{distance}{time}$

Second row.

From the second row of the table $time = \frac{1}{2}=0.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{0.5}$

$distance = 55\times 0.5$

$distance = 27.5\ mi$

Third row.

From the third row of the table $time =1\frac{1}{2}=\frac{3}{2} = 1.5\ sec$ and speed is constant $speed = 55\ mi/hr$ , so we need to find only distance.

$Speed=\frac{distance}{time}$

$55=\frac{distance}{1.5}$

$distance = 55\times 1.5$

$distance = 82.5\ mi$

Fourth row.

From the fourth row of the table $distance =110\ miles$ and speed is constant $speed = 55\ mi/hr$ , so we need to find time.

$Speed=\frac{distance}{time}$

$time=\frac{distance}{speed}$

$time=\frac{110}{55}$

$time = 2\ sec$

Therefore we complete the table from the above calculation.

8 0

3 years ago

Linda purchase a prepaid phone card for $30. Long distance calls cost $.17 a minute using this card when do use her card. Linda

balandron [24]

Answer: her call lasted for 44 minutes

Step-by-step explanation:

Linda purchase a prepaid phone card for $30. This means that the credit on her card is $30.

Long distance calls cost $0.17 each. Linda use her card only to make a long distance call. Assuming she made a total of x minutes of long distance calls, the cost would be $0.17x. The amount remaining on her card will be

30 - 0.17x

if the remaining credit on her card is $22.52, the number of minutes,x that the call lasted will be

22.52 = 30 - 0.17x

0.17x = 30 - 22.52

0.17x = 7.48

x = 7.48/0.17 = 44

7 0

3 years ago