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Andreyy89
1 year ago
9

Free poînts lol Philippînes - cool​

Engineering
1 answer:
polet [3.4K]1 year ago
8 0

Answer:

ddjxjxjdduududjdusjdhdudjdbdhd

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Write a program that dynamically allocates an array large enough to hold a user-defined number of test scores. Once all the scor
Readme [11.4K]

Answer:

#include <iostream>

#include <iomanip>

using namespace std;

//Function prototypes

void arrSelectSort(double *, int);

double arrAvgScore(double *, int);

int main()

{  

//Variables  definition

double *TestScores,  

total = 0.0,

average;

int numTest,

count;

//Enter the number of test scores you want to get to their average in ascending order

cout << "How many test scores do you wish to enter?";

cin >> numTest;

//Dynamically allocate an array large enough to hold that many scores

TestScores = new double[numTest];

//Get the test scores

cout << "Enter the test scores below.\n";

for (count = 0; count < numTest; count++)

{

//Display score

cout << "Test Score " << (count + 1) << ": ";

cin >> TestScores[count];

 }  

// Input validation. Only numbers between 0-100

while (numTest<0)

{

cout << "You must enter a scores that non-negative" << endl;

cout << "Please enter a non-negative interger between 0 and 100: ";

cin >> TestScores[count];

}

//Calculate the total test scores

for (count = 0; count < numTest; count++)

{

total += TestScores[count];

}

average = total / numTest;

//Dsiplay the results

cout << fixed << showpoint << setprecision(2);

cout << "The average of all the test score is " << average << endl;

//Free dynamically allocated memory

delete [] TestScores;

TestScores = 0; //make TestScores point to null

//Display the Test Scores in ascending order

cout << "The test scores, sorted in ascending order, are: \n";

system ("pause");

return 0;

}

//Ascending order selection sort

void arrSelectSort(double *arr, int size)

{

int startScan;

double minIndex;

double minElem;  

for(startScan = 0; startScan < (size - 1); startScan++)

{

minIndex = startScan;

minElem = arr[startScan];  

}

for(int index = startScan + 1; index < size; index++)

{

if (arr[index] < minElem)

{

minElem = arr[index];

minIndex = index;  

}

}

void arrAvgScore (double *arr[], int size)

{

double total = 0;

int numTest;

for (int count = 0; count < numTest; count++)

{

total += numTest[count];

average = total / numTest;

}

}

}

6 0
4 years ago
The rectangular frame is composed of four perimeter two-force members and two cables AC and BD which are incapable of supporting
Rama09 [41]

Answer:

Your question is lacking some information attached is the missing part and the solution

A) AB = AD = BD = 0, BC = LC

    AC = \frac{5L}{3}T, CD = \frac{4L}{3} C

B) AB = AD = BC = BD = 0

   AC = \frac{5L}{3} T, CD = \frac{4L}{3} C

Explanation:

A) Forces in all members due to the load L in position A

assuming that BD goes slack from an inspection of Joint B

AB = 0 and BC = LC from Joint D, AD = 0 and CD = 4L/3 C

B) steps to arrive to the answer is attached below

AB = AD = BC = BD = 0

AC = \frac{5L}{3} T,  CD = \frac{4L}{3}C

7 0
4 years ago
What type(s) of bonding would be expected for each of the following materials?
Verdich [7]

Answer:

Rubber:Covalent bonding

Barium sulfide:ionic bonding

Solid xenon: Van daar Waal bond.

Bronze:Metallic bond

Nylon:Covalent bonding

Aluminum phosphate: mixture of ionic and covalent bond

Explanation:

Rubber is mainly composed of isoprene which is predominantly covalent bond

Barium sulphide is predominantly ionic bonding

Is xenon is inert its bond is van daar Waal

Bronze is an alloy of metal usually held by metallic boding

Nylon:covalent bonding

Aluminium phosphate have a mixture of covalent and ionic bond

8 0
3 years ago
Why does the author introduce the grandmother with her comments about the Misfit? (paragraph 1)
zimovet [89]

Answer:

Grandmother has her opinions set in stone. Her early comments on the misfit are central to the irony of what actually unfolds. Despite her belief in Christian grace and forgiveness, her world will still implode.

Explanation:

hope this helped you (ㆁωㆁ)

7 0
4 years ago
The formula for calculating risk considering risk perception is ?​
s2008m [1.1K]

Answer:

risk = probability x loss

Explanation:

3 0
3 years ago
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