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yarga [219]
3 years ago
15

A slight breeze is blowing over the hot tub above and yields a heat transfer coefficient h of 20 W/m2 -K. The air temperature is

75 F. If the surface area of the hot tub is 7.5 m2 , what is the heat loss (heat rate) due to convection? The temp of Hot Tube is 102F.
Engineering
1 answer:
patriot [66]3 years ago
7 0

Answer:4050 W

Explanation:

Given

Heat transfer Coefficient(h)=20 W/m^2-K

Air temperature =75 F

surface area(A)=7.5 m^2

Temperature of hot tube is 102 F

We know heat transfer due to convection is given by

Q=hA\left ( \Delta T\right )

Q=20\times 7.5\left ( 102-75\right )=4050 W

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