Answer and Explanation:
Given : Sides of right triangle 5,12 and 13.
To find : Show that the area of a right triangle of sides 5, 12 and 13 cannot be a square ?
Solution :
If 5,12 and 13 are sides of a right angle triangle then
13 is the hypotenuse as it is largest side.
then we take perpendicular as 12 and base as 5.
The area of the right angle triangle is
Here, h=12 and b=5
The area of the right angle triangle is 30 units.
30 is not a perfect square as 
There is no square pair formed.
We have two classrooms and seven packages.
This means we need to divide the seven packages in half (two pieces).
7packages ÷ 2 classrooms = 7/2 = 3.5 packages per class
(three and a half packages)
Answer:
4x^4y + 20x^2y^2 - 28x^3y
Step-by-step explanation:
4xy(x^3 + 5xy - 7x^2)
= 4xyx^3 + 4xy * 5xy - 4xy * 7x^2
= 4x^2y + 4xy * 5xy - 4xy * 7x^2
= 4x^4y + 20x^2y^2 - 4xy * 7x^2
= 4x^4y + 20x^2y^2 - 28x^3y
If a=0, then the denominator is equal to 0. Since you cannot divide by zero, you are not allowed to do this.
Answer:
Step-by-step explanation:
we know that
A binomial is a Difference of Squares if both terms are perfect squares
we have
so
---> is a perfect square
----> is a perfect square
Both terms are perfect squares
The difference of squares is
----> by difference of squares
