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3 years ago

Which inequality is represented by this graph?

Mathematics

1 answer:

Marrrta [24]3 years ago

7 0

Answer:

x greater than or equal to 4

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Can I get a pog for reaching ambitious rank?

Bumek [7]

Answer:

Yeah pretty sure

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3 years ago

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In the adjoining figure, XY = XZ . YQ and ZP are the bisectors of <img src="https://tex.z-dn.net/?f=%20%5Cangle" id="TexFormula1

svetlana [45]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$1)\, XY=XZ$ Given

$2) \text{ $ m\angle Y= m\angle Z$}$ Isosceles Triangle Theorem

$\displaystyle 3) \text{ $m\angle Y=m\angle XYQ + \angle QYZ$}$ Angle Addition

$\displaystyle 4)\text{ $YQ$ bisects $\angle XYZ$}$ Given

$5) \text{ $m\angle XYQ=m\angle QYZ$}$ Definition of Bisector

$\displaystyle 6)\text{ $m\angle Y=2m\angle QYZ$}$ Substitution

$7)\text{ $m\angle Z=m\angle XZP+m\angle PZY$}$ Angle Addition

$8)\text{ $ZP$ bisects $\angle XZY$}$ Given

$\displaystyle 9) \text{ $m\angle XZP=m\angle PZY$ }$ Definition of Bisector

$\displaystyle 10) \text{ $ m\angle Z = 2m\angle PZY $}$ Substitution

$11)\text{ } 2m\angle QYZ=2m\angle PZY$ Substitution

$12)\text{ }m\angle QYZ=m\angle PZY$ Division Property of Equality

$13)\text{ } YZ=YZ$ Reflexive Property

$14)\text{ } \Delta YZP\cong\Delta ZYQ$ Angle-Side-Angle Congruence*

$15)\text{ } YQ=ZP$ CPCTC

*For clarification:

∠Y = ∠Z

YZ = YZ (or ZY)

∠PZY = ∠QYZ

So, Angle-Side-Angle Congruence:

ΔYZP is congruent to ΔZYQ

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3 years ago

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bryans aquarium is 6 feet long, 4 feet wide and 5 feet high, how many cubic feet of water can the tank hold?

SashulF [63]

6 x 4 x 5 = 120 cubic feet of water

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3 years ago

The sum of two numbers is 27. One number is 3 more than the other. Write and solve a system of equations to find the two numbers

givi [52]

X + y = 27
x = y + 3

y + 3 + y = 27
2y + 3 = 27
2y = 27 - 3
2y = 24
y = 24/2
y = 12

x = y + 3
x = 12 + 3
x = 15

ur numbers are 12 and 15

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3 years ago

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Solve the equation below for x: - 3/ x+2 = 7 /x+5

victus00 [196]

Answer:

X = -29/10

Step-by-step explanation:

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