Heya!!!!
Answer to your question:
2+2=4
Hope it helps *_*
The number of Hamilton Circuits with 8 vertices are 5040.
Given that, a complete, weighted graph with 8 vertices.
<h3>What are Hamilton Circuits?</h3>
A Hamiltonian circuit is a circuit that visits every vertex once with no repeats. Being a circuit, it must start and end at the same vertex. A Hamiltonian path also visits every vertex once with no repeats, but does not have to start and end at the same vertex.
For N vertices in a complete graph, there will be (n−1)!=(n−1)(n−2)(n−3)…3⋅2⋅1 routes. Half of these are duplicates in reverse order, so there are (n−1)!/2 unique circuits.
A complete graph with 8 vertices would have = 5040 possible Hamiltonian circuits. Half of the circuits are duplicates of other circuits but in reverse order, leaving 2520 unique routes.
Therefore, the number of Hamilton Circuits with 8 vertices are 5040.
Learn more about the Hamilton Circuits here:
brainly.com/question/24725745.
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8x = 36 + 18y ⇒ -2(8x = 36 + 18y) ⇒ -16x = -72 - 36y
9x = 28 + 4y ⇒ 9(9x = 28 + 4y) ⇒ <u> 81x</u> = <u>252 + 36y</u>
65x = 180
x = 
9x = 28 + 4y
9
= 28 + 4y
9(36) = 13(28 + 4y)
324 = 364 + 52y
-40 = 52y
Answer: x = , y = 
Essentially the question is answering itself here > <span>F(x) is very large negative number.</span>
Answer:
1. 0=0
2. x= -3
3. 14=0
Step-by-step explanation:
I tried I'm sorry if it's wrong
