Ur equations are :
C = 0.03t + 20...this is company A
C = 0.07t + 5....this is company B
now...for them to be equal...set them equal and solve for t
0.03t + 20 = .07t + 5
-5 + 20 = 0.07t - 0.03t
15 = 0.04t
15/0.04 = t
375 = t.......there would have to be 375 texts
Answer:
4
Step-by-step explanation:
Equation 1
Equation 2
What is the value of 
where each variable represents a real number?
Let's expand equation 1:
Simplify each term if can:
See if we can factor a little to get some of the left hand side of equation 2:
The first two terms have 
and if I factored from first two terms I would have 
which is the first term of left hand side of equation 2.
So let's see what happens if we gather the terms together that have the same variable squared together.
Factor the variable squared terms out of each binomial pairing:
Replace the sum of those first three terms with what it equals which is 6 from the equation 2:
Combine like terms:
Subtract 6 on both sides:
Divide both sides by 3:
3.14(3(2) + 3(4))
3.14( 6 + 12)
3.14(18)
=56.52
Add all 3 and you get 264 then divide by 3 and you get 88
You should write numbers in as many ways as you possibly can to make new connections in your brain. Knowing how to write numbers in many different ways can help you solve complex problems more easily. Doing this can also reinforce the mathematical principles and logic you have memorised.
Writing one in many different ways:
1=1/1=2/2=3/3=4/4=(-1)/(-1)=(-2)/(-2)
=1.0=1.00=1.000=(1/2)+(1/2)=(1/3)+(1/3)+(1/3)
=(1/4)+(1/4)+(1/4)+(1/4)
Writing a half in many different ways:
1/2=(1/4)+(1/4)=(1/6)+(1/6)+(1/6)
=(1/8)+(1/8)+(1/8)+(1/8)=4*(1/8)
=2/4=3/6=4/8=5/10=0.5=0.50
etc...etc...
