Answer:
Step-by-step explanation:
Use synthetic division to answer this. If the remainder is zero, then we can safely assume the divisor (x + 7) is a factor of the polynomial f(x)= x^3-3x^2+2x-8.
We use -7 as the divisor in synth. div. This comes from the factor (x + 7):
-7 / 1 3 2 -8
-7 28 -210
-------------------------
1 -4 30 -218
Here, the remainder is -218, not zero, so no, (x+7) is not a factor of f(x)= x^3-3x^2+2x-8.
Answer:
7x² - 6x + 4
Step-by-step explanation:
(4x² - x + 6) - (-3x² + 5x + 2)
4x² - x + 6 + 3x² - 5x - 2
4x² + 3x² - x - 5x + 6 - 2
7x² - 6x + 4
The answer would be c)x+3 because if you substitute 1 for x, the expression would be 1+3 and it comes out as 4. Also, if you substitute 4 for x the expression would be 4+3 which comes out to 7
Hope this helps!