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3 years ago

A.1 B. 2/3 C.5/6 D.1/3

Mathematics

2 answers:

RideAnS [48]3 years ago

8 0

Answer:

Step-by-step explanation:

There are 6 values on the faces of a standard number cube, that is

1, 2, 3, 4, 5, 6

There are 4 values > 2, that is 3, 4, 5, 6

P( number > 2 ) = $\frac{4}{6}$ = $\frac{2}{3}$ → B

Elodia [21]3 years ago

5 0

Answer:

B. 2/3

Step-by-step explanation:

A standard cube has 6 sides, numbered 1 - 6. You are finding the probability (P) of getting a number greater than 2. Note that it says "greater than" not "greater and equal", so you do not count 2 inside the answer.

3, 4, 5, 6, are all greater than 2, and are 4 of the 6 numbers provided. Simplify the fraction:

(4/6)/(2/2) = 2/3

B. 2/3 is your answer.

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4 years ago

Using the binomial theorem , obtain the expansion of :

andrezito [222]

Answer:

see explanation

Step-by-step explanation:

Expand both factors and collect like term

Using Pascal' triangle with n = 6 to obtain the coefficients

1 6 15 20 15 6 1

Decreasing powers of 1 from $1^{6}$ to $1^{0}$

Increasing powers of 3x from $(3x)^{0}$ to $(3x)^{6}$

$1+3x)^{6}$

= 1. $1^{6}$ $(3x)^{0}$ + 6. $1^{5}$ $(3x)^{1}$ + 15. $1^{4}$ $(3x)^{2}$ + 20. $1^{3}$ $(3x)^{3}$ + 15.1² $(3x)^{4}$ + 6. $1^{1}$ $(3x)^{5}$ + 1. $1^{0}$ $(3x)^{6}$

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--------------------------------------------------------------------------------------

$(1-3x)^{6}$

= 1. $1^{6}$ $(-3x)^{0}$ + 6. $1^{5}$ $(-3x)^{1}$ + 15. $1^{4}$ $(-3x)^{2}$ + 20. $1^{3}$ $(-3x)^{3}$ + 15.1² $(-3x)^{4}$ + 6. $1^{1}$ $(-3x)^{5}$ + 1. $1^{0}$ $(-3x)^{6}$