The weights of 5 girls are 70 pounds, 68 pounds, 85 pounds, 62 pounds, and 70 pounds. Nina finds measures of center and measures
of variation of this data. Match the descriptions to the type of measure.
1. She found the difference of the least
and the greatest values.
2. She found the middle value after
arranging all the values from least
to greatest.
3. She added all the values and divided the
sum by 5.
4. She found the value that appeared the
most often.
5. She found the difference of the
upper quartile and the lower
quartile.
6. She found the mean and then
found the average deviation of
the weights from the mean.
Measure of center or measure of variation?
1. She found the difference of the least
and the greatest values.
2. She found the middle value after
arranging all the values from least
to greatest.
3. She added all the values and divided the
sum by 5.
4. She found the value that appeared the
most often.
5. She found the difference of the
upper quartile and the lower
quartile.
6. She found the mean and then
found the average deviation of
the weights from the mean.
Measure of center or measure of variation?
1 answer:
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if you isolate y in the top equation to get y=5x+6 then you can substiture y for 5x+6 in the bottom equation because thats what y equals
as of now you have -3x+6(5x+6)=-12 but if you use the distrubite property you would get -3x+30x+36=-12
then if you subtract 36 from both sides you would get -3x+30x=-48 then combine like terms to get 27x=-48 then divide both sides by 27 to get or x≈1.8