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3 years ago

Using interval notation , identify the domain for the function!!! Math 3 - 10 points. Help needed

Mathematics

1 answer:

In-s [12.5K]3 years ago

7 0

Answer:

The domain by the interval notation is (-∞ , 3)∪(3 , 4)∪(4 , ∞) ⇒ 3rd answer

Step-by-step explanation:

* Lets revise how to find the domain of the function

- The domain is all values of x that make the expression defined

- To find where the expression is undefined put the denominator

equal 0, to get the values of x which make denominator equal to 0

- The domain will be all the real number except those values

* Now lets solve the problem

∵ f(x) = (x² - 9)/(x² - 7x + 12)

- Let the denominator x² − 7x + 12 equal to 0

∵ x² − 7x + 12 = 0 ⇒ factorize it

- Consider the form x² + bx + c

- Find a pair of integers whose product is c and whose sum is b

- In this case, whose product is 12 and whose sum is −7

- They are -3 and -4

- Write the factored form using these integers.

∴ (x -3)(x - 4) = 0 ⇒ put each bracket = 0

∴ x - 3 = 0 or x - 4 = 0

∵ x - 3 = 0 ⇒ add 3 to both sides

∴ x = 3

∵ x - 4 = 0 ⇒ add 4 to both sides

∴ x = 4

∴ The domain of f(x) is all real number except 3 and 4

* The domain by the interval notation is

(-∞ , 3)∪(3 , 4)∪(4 , ∞)

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3 years ago

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pychu [463]

Answer:

$P(A_1 = A_2 =A_3) = \frac{1}{1-\frac{1}{8}} -1 =\frac{1}{7}$

Step-by-step explanation:

For this case we assume that the probability of obtain a head is 1/2

$P(H) =\frac{1}{2}$

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Now we need to assume that the 3 performaces are independent from each other and we want this:

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And we can since we have the mass function we can replace:

$P(A_1 = A_2 =A_3) =\sum_{r=1} (\frac{1}{2})^{3r}$

$P(A_1 = A_2 =A_3) = \sum_{r=1} (\frac{1}{8})^r$

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4 years ago

The circumference of a circle is 3π in. What is the area of the circle? 1.5π in² 2.25π in² 6π in² 9π in²

dangina [55]

C = 2πr
so
r = C/2π
r = 3π/2π
r = 3/2
r = 1.5

A = πr^2
A = π(1.5)^2
A = 2.25π

answer
2.25π in²

3 0

3 years ago

Read 2 more answers

Events A and B are disjointed. P(A) = 4/11; P(B) = 3/11, P(A and B)= 2/11 . Find P(A or B).

Anettt [7]

Answer:

$P(A\:or\:B)=\frac{7}{11}$

Step-by-step explanation:

If the two events are disjoint, then P(A or B)=P(A)+P(B).

We were given that:

$P(A)=\frac{4}{11}$

and

$P(B)=\frac{3}{11}$

This implies that:

$P(A\:or\:B)=\frac{4}{11}+\frac{3}{11}$

We simplify the right hand side to obtain:

$P(A\:or\:B)=\frac{4+3}{11}$

$P(A\:or\:B)=\frac{7}{11}$

8 0

3 years ago