Which one first show me your problem
Answer:
see explanation
Step-by-step explanation:
Under a reflection in the x- axis
a point (x, y ) → (x, - y ) , then
A (- 1, - 5 ) → A' (- 1, 5 )
B (2, - 3 ) → B' (2, 3 )
C (3, - 5 ) → C' (3, 5 )
Under a reflection in the y- axis
a point (x, y ) → (- x, y ) , then
A' (- 1, 5 ) → A'' (1, 5 )
B' (2, 3 ) → B'' (- 2, 3 )
C' (3, 5 ) → C'' ( - 3, 5 )
Answer: 1% red and 3% orange
explanation:
Not sure if its right but did my best!!
we have
<u>Statements</u>
<u>case A)</u> The graph is a straight line.
The statement is True
Because, this is a linear equation (see the attached figure)
<u>case B)</u> The line passes through the origin.
The statement is False
Because the point is not a solution of the equation
Verify
Substitute the value of x and y in the equation
------> is not true
the point is not a solution
therefore
The line does not pass through the origin
<u>case C)</u> The line passes through the point
The statement is True
Because the point is a solution of the equation
Verify
Substitute the value of x and y in the equation
------> is true
the point is a solution
therefore
The line passes through the point
<u>case D) </u>The slope of the line is
The statement is False
Because, the slope of the line is
<u>case E)</u> The y-intercept of the line is
The statement is False
we know that
The y-intercept is the value of y when the value of x is equal to zero
so
For
find the value of y
the y-intercept is equal to