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Alex17521 [72]
1 year ago
6

What is the decimal equivalent of each rational number a.7/20 b.-23/20 c.1/18 d.-60/22

Mathematics
1 answer:
Eva8 [605]1 year ago
4 0

Answer:

a. 0.35

b. -1.15

c. 0.056

d. -2.727

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Answer: 3x + (-4) = x + 2

Step-by-step explanation:

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Find x Help ASAP ASAP
Blizzard [7]

the given figure is a rhombus, so it's area =

\frac{1}{2}  \times \: d1 \times d2

where, d1 and d2 are diagonals of the rhombus,

and since, the diagnonals of rhombus bisects each other, the values of their diagonals are

(2 × x) and (2 × 15) =》2x and 30 respectively,

so, by finding the area using the given diagonals and equating it with the real area, we get :

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\frac{1}{2}  \times 2x \times 30 = 300

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value of x = 10 units

4 0
3 years ago
Oliver interviewed 30% of the 9th grade class and 70% of the 10th grade class at his school. Jenny interviewed 75% of the 9th gr
mixer [17]

Answer:

A . 36

Step-by-step explanation:

We are given a total of 176 interviewed by Oliver and a total of 140 interviewed by Jenny. To find how many more 10th graders than 9th graders were interviewed, subtract the totals given

176 - 140 = 36

This is how we came to the answer:

We are given 70% of the 10th-grade and 30% of the 9th-grade with a total of 176 for Oliver.

While we're given 75% of the 9th-grade class and 25% of the 10th-grade with a total of 140 interviewed by Jenny

<u>Oliver's Interviewees</u>

  • 10-graders

Firstly, let's find what the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

70% of 176 =

\frac{70}{100} * \frac{176}{1}

Cross multiply

123.2 were 10-graders interviewed by Oliver

  • 9th-graders

Now, to find the number of 9th-graders was interviewed by Oliver; find the percentage of the 9th-graders by the total;

30% of 176 =

\frac{30}{100} * \frac{176}{1}

Cross multiply

52.8 were 9th-graders interviewed by Oliver

<u>Jenny's Interviewees</u>

  • 9th-graders

Firstly, let's find what the number of 9th-graders was interviewed by Jenney; find the percentage of the 9th-graders by the total;

75% of 140 =

\frac{75}{100} * \frac{140}{1}

Cross multiply

105 students were 9th-graders interviewed by Jenney.

  • 10th-graders

Now, to find the number of 10th-graders was interviewed by Jenney; find the percentage of the 10th-graders by the total;

25% of 140 =

\frac{25}{100} * \frac{140}{1}

Cross multiply

35 students were 10th-graders interviewed by Jenney.

<u />

<u>Total calculation</u>

Use the results and sum them up by 9th-grade plus 9th-grade and 10th-grade plus 10-grade. Then subtract the amount gotten from 9th-grade away from the amount gotten from 10th-grade;

Oliver's 9th-grade = 52.8

Jenny's 9th-grade = 105

105 + 52.8 = 157.8

Oliver's 10th-grade = 123.2

Jenny's 10th-grade = 35

123.2 + 35 = 158.2

Total calculation: 158. 2 - 157.8 = 0.4

<h2>Therefore, there are 36 more 10th than 9th.</h2>

<u />

<h3><u>Extra Info:</u></h3>

<u>Oliver's Interviewees Percentage</u>

Since we are given 30% of the 9th-grade class and 70% of the 10th-grade class, first, let's add the percentages. To do so, set it up as a fraction;

30% = \frac{30}{100} while, 70% = \frac{70}{100}

Now solve it;

\frac{30}{100} + \frac{70}{100}

Simplify; cancel bottom zero's;

\frac{30}{1} + \frac{70}{1}

Add the remaining numerators;

30 + 70 = 100

Which is 100%

<u>Jenny's Interviewees Percentage</u>

Since we're given 75% of the 9th-grade class and 25% of the 10th-grade, it will end up the same answer. I'll show you how; first, let's add the percentages. To do so, set it up as a fraction;

25% = \frac{25}{100} and, 75% = \frac{75}{100}

Now solve it;

\frac{25}{100} + \frac{75}{100}

Simplify; cancel bottom zero's

\frac{25}{1} + \frac{75}{1}

Add the remaining numerators;

25 + 75 = 100

Meaning 100%

5 0
3 years ago
A sequence is a function whose domain is the set of ____ numbers.<br> Answer h
amm1812

Answer:

Step-by-step explanation:

... integer ...

The only variable in a sequence is the index, usually written as n, which is {1, 2, 3, 4, ... }

7 0
3 years ago
How many triangles can be constructed with side lengths of 7 cm, 10 cm, and 18 cm?
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B. Only one can be made but can be rotated to look like different.
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3 years ago
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