A man earned $4000 the first year he worked. If he received a raise of $600 at the end of each year, what was his salary during
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Answer:
Step-by-step explanation:
+6x-5=0
we divide the coefficient of the X by half :
in this case: 6/2 = 3 , then we do the following
The result obtained is raised to square power: 3^2=9
we sum and subtract by 9 to maintain the balance of the equation:
+6x+9-9-5=0
we have:
-9-5=0
= 14
lets apply square root on both sides of the equation:
we know:
so we have:
abs(x+3)=
from where two solutions are obtained
finally we have:
