The estimate would be 1200.
We will set up a proportion for this. 10 out of 60 of the sample were tagged, so that is the first ratio. The 200 that were tagged would be in the numerator of the second ratio (10 was the portion tagged, and 200 is the portion tagged, so they both go on top). We do not know the total number so we use a variable:
10/60 = x/200
Cross multiply:
10*x = 60*200
10x = 12000
Divide both sides by 10:
10x/10 = 12000/10
x = 1200
They probably want 880 pesos, since they asked you do intermediate rounding
but a more accurate answer would be
883.20 pesos
To combine the functions, you'd substitute in 2.76r for y in 0.16y. This would give you 0.16(2.76r), which simplifies to 0.4416r, but they want you round this to the nearest hundredth, so its really 0.44r. Substitute in the 2000 for r and you get 0.44 * 2000 which is 880 pesos
Answer: The second graph
In all but the 3 graphs, the data is perfectly symmetrical. This means that the mean and the median would be the same.
However, in the second graph the data is skewed to the right. This means that the mean would also be skewed to the right due to the larger scores there. Using the median in this case would give a clearer picture of the data.
Answer:
(2,3)
Step-by-step explanation:
this is the only coordinate that can be plugged in and still be true. therefore, this is the only value that intersect and creates a point.
Answer:
B.63 and A. 36
Step-by-step explanation:
