The 15th term in the given A.P. sequence is a₁₅ = 33.
According to the statement
we have given that the A.P. Series with the a = 5 and the d is 2.
And we have to find the 15th term of the sequence.
So, for this purpose we know that the
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is a
an = a + (n-1)d
After substitute the values in it the equation become
an = 5 + (15-1)2
a₁₅ = 5 + 28
Now the 15th term is a₁₅ = 33.
So, The 15th term in the given A.P. sequence is a₁₅ = 33.
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Answer:
<h2>2400GH Cedis </h2>
Step-by-step explanation:

Answer:
D. Length = 9 cm; width = 6 cm
Step-by-step explanation:
Find 1/4 of the length and 1/4 of the width.
1/4 * 36 cm = 9 cm
1/4 * 24 cm = 6 cm
Answer: D. Length = 9 cm; width = 6 cm
Answer:
Step-by-step explanation:
if there are 14 boys to 9 girls in a class the ratio would be
14:9
Answer:
1.5
Step-by-step explanation:
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