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2 years ago

All the numbers that round to 940,000 when rounded to the nearest ten thousand?

Mathematics

1 answer:

timurjin [86]2 years ago

7 0

The required number is 940,000.

It is required to find the solution.

<h3>What is rounded number?</h3>

A number that is easily multiplied, divided, etc., and especially a number that ends in zero.

Solution:

To round a number to the nearest 10,000, check the thousands digit to decide whether to round up or round down. If the thousands are 5000 or more, round up. If they are 4999 or less, round down. 45,000 to the nearest 10,000 is 50,000.

The numbers that round to 940,000 when rounded to the nearest ten thousand is 940,000.

Therefore, the required number is 940,000.

Learn more about rounded number here:

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Clare is paid $90 for 5 hours of work. At thos rate how many seconds does i take for her to earn 25 cents?

natka813 [3]

We are given

Clare is paid $90 for 5 hours of work

Total money paid =$90

total hours of work =5 hours

so, firstly we will find rate of work

rate of work = ( total money paid)/( total hours of work)

now, we can plug values

and we get

The rate of work is

$=\frac{90}{5}$

$=18$ $/ hour

now, we have to find time for amount paid is 25 cents

so, amount paid =25 cents

100 cents =1$

so, amount paid =$ 0.25

Since, the rate is constant

so, we can take same rate here

now, we can use formula

rate of work = ( total money paid)/( total hours of work)

now, we can plug values

$18=\frac{0.25}{T}$

now, we can solve for T

$T=\frac{0.25}{18}$ hour

since, T is in hours

so, we can change into seconds

1 hour =3600seconds

so, we can plug

$T=\frac{0.25}{18}\times 3600$ seconds

$T=50$ seconds......................Answer

6 0

3 years ago

The 10th term in the sequence is 2560 what is the 11th term in the sequence

joja [24]

Full Question:

The 4th term of a g.p. is 40 and the 10th term in the sequence is 2560, what is the 11th term in the sequence ?

Answer:

the 11 the term is 5120

Step-by-step explanation:

Given

Geometry Progression

4th term = 40

10th term = 2560

Required

11 term.

The nth term of a geometric sequence is calculated as follows

Tₙ = arⁿ⁻¹

For the 4th term, n = 4 and Tₙ = 40

Substitute these in the given formula; this gives

40 = ar⁴⁻¹

40 = ar³. --;; equation 1

For the 10th term, n = 10 and Tₙ = 2560

Substitute these in the given formula; this gives

2560 = ar¹⁰⁻¹

2560 = ar⁹. --;; equation 2

Divide equation 2 by 1. This gives

2560/40 = ar⁹/ar³

64 = r⁹/r³

From laws of indices

64 = r⁹⁻³

64 = r⁶

Find 6th root of both sides

(64)^1/6 = r

r = (2⁶)^1/6

r = 2

Substitute r = 2 in equation 1

40 = ar³. Becomes

40 = a * 2³

40 = a * 8

40 = 8a

Divide both sides by 8

40/8 = 8a/8

5 = a

a = 5.

Now, the 11 term can be solved using Tₙ = arⁿ⁻¹ where n = 11

So,

Tₙ = arⁿ⁻¹ becomes

Tₙ = 5 * 2¹¹⁻¹

Tₙ = 5 * 2¹⁰

Tₙ = 5 * 1024

Tₙ = 5120.

Henxe, the 11 the term is 5120

5 0

3 years ago

Devonte used the change of base formula to approximate log Subscript 8 Baseline 25. Which expression did Devonte use?

Travka [436]

$\frac{log 25}{log 8}$ is the expression Devonte used the change of base formula to approximate log Subscript 8 Baseline 25.

Given that, Devonte used the change of base formula to approximate log Subscript 8 Baseline 25.

We need to determine the expression did Devonte use.

<h3>What is the formula of change of base formula?</h3>

The change of base formula says $log_{a} b=\frac{log_{c}b }{log_{c}a}$ . It means to change the base of a logarithm logb b a, we just use division $\frac{log a}{log b}$ where these logarithms can have any positive number as a base.