Answer: 16 square units
Step-by-step explanation:
let the vertex in quadrant I be (x,y)
then the vertex in quadratnt II is (-x,y)
base of the rectangle = 2x
height of the rectangle = y
Area = xy
= x(12 - x²)
= -x³ + 12x
d(area)/dx = 3x² - 12 = 0 for a maximum of area
3x² = 12
x² = 4
x = ±2
y = 12-4 = 8
So, the largest area = 2 x 8 = 16 square units
Answer:
need points im really sorry
Step-by-step explanation:
jk mate its 3.75
Answer:
The hypotenuse is 5
Step-by-step explanation:
We can use the Pythagorean theorem to find the hypotenuse of a right triangle
a^2 +b^2 =c^2 where a and b are the legs and c is the hypotenuse
3^2 +4^2 =c^2
9+16=c^2
25=c^2
Take the square root of each side
sqrt(25) =sqrt(c^2)
5 = c
Answer:
Step-by-step explanation:
((14×3) + 1 )/3 = (43/3)
