Answer:
2 N/newtons of force
Explanation:
2kg x 0.5m/s/s = 2 N/newtons of force
<span>Mercury: 0.38
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The option that describes the relationship between the two confidence intervals is; The width of I₈₁ will be¹/₉ the width of I₉
<h3>How to calculate width of the confidence interval with normal distribution?</h3>
The width of the confidence interval will be calculated from the formula;
W = 2Z(σ/√n)
where;
z is the z-score at given confidence level
σ is standard deviation
n is sample size
For first sample;
W_i9 = 2Z(σ/√9)
W_i9 = ²/₃Zσ
For second Sample;
W_i81 = 2Z(σ/√81)
W_i81 = ²/₉Zσ
Thus, we will have;
W_i9/W_i81 = (²/₃Zσ)/(²/₉Zσ)
W_i9/W_i81 = 9
W_i81 = ¹/₉W_i9
Read more about width of confidence interval at; brainly.com/question/15934877
Answer:
can you please post the picture for this thank you and