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MatroZZZ [7]
1 year ago
10

Helppppppp Plssssswwww

Mathematics
1 answer:
Irina18 [472]1 year ago
6 0

Answer: No Hope this helps, please consider making me Brainliest.

Step-by-step explanation:

If it is not proportional, it will not cross the origin (I remember this data from the other question you posted). Hope this helps, please consider making me Brainliest.

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If a4a3 is divisible by 11, what is a?(a is a number)
Olin [163]
Hindi ko po maintindihan Ang question nyo
5 0
2 years ago
What is the area of the square
ahrayia [7]

Answer:

56 - 6√12

Step-by-step explanation:

If s = side length = √2 - 3√6, then:

A = area of square = s² = (√2 - 3√6)²

                                       = (√2 - 3√6)(√2 - 3√6)

                                       = 2 - 3√12 - 3√12 + 9(6)

                                        = 2 - 6√12 + 54, or

                                        = 56 - 6√12 is the area of the square.

5 0
3 years ago
The arrow on the spinner is to be spun once.
Gnom [1K]
C because probabilty means the best out of so theres 2 numbers  that are less than three hope i helped.
7 0
3 years ago
A machine is used to fill 1-liter bottles of a type of soft drink. We can assume that the output of the machine approximately fo
allsm [11]

Answer:

1.00434

Step-by-step explanation:

Given the following :

Given a normal distribution ;

Mean (m) = 1.0 liter

Standard deviation (σ) = 0.01 liter

Sample size (n) = 25

For 97% sample means (sm) = 0.97

Z = (m - sm) / s

Zcrit = 1 - (100% - 97%)/2

Zcrit = 1 - (0.03/2)

Zcrit = 1 - 0.015 = 0.985

The z score which corresponds to 0.985 = 2.17

Upper limit : m + z*(σ/√n)

Upper limit : 1.0 + 2.17*(0.01/√25)

Upper limit : 1. 0 + 2.17*(0.01/5)

= 1.0 + 2.17*0.002

= 1.0 + 0.00434

= 1.00434

3 0
3 years ago
Suppose the names of the months of the year are placed in a hat and a name is drawn at random. (a) list the sample space for thi
ollegr [7]

(a)

The sample space is a set whose elements are all the possible outcomes for the experiment. Since we will extract one of the months of the years, the sample space is the set composed by all the 12 months:

\Omega = \{ \text{January},\ \text{February},\ldots,\text{December}\}

(b)

An event is a subset of the sample space. Events are often defined by their properties. In this example, the event E is the subset of the sample space defined as

E = \{ x \in \Omega: x \text{ starts with the letter J}\}

So, we have

E = \{\text{January},\ \text{June},\ \text{July}\}

(c)

If all outcomes have equal probability, then the probability of an event is the ratio bewteen its cardinality, and the cardinality of the whole sample space:

P(E) = \dfrac{n(E)}{n(\Omega)} = \dfrac{3}{12} = \dfrac{1}{4}

In words, since there are three months beginning with J out of 12 months, we have a probability of 3 over 12 to pick a month starting with J, which simplifies to 1 over 4.

3 0
3 years ago
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