11. If A, B, and C are any three sets, then show that, (a (BA)U(C-A) = (BUc)-A

Mathematics

2 answers:

docker41 [41]2 years ago

8 0

ave njfdjn kkgffnk jyffh

Arlecino [84]2 years ago

8 0

Answer:

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When the outliers are removed, how does the mean change?

jok3333 [9.3K]

In statistics, an outlier is an observation point that is distant from other observations.

Given the points
15, 23, 24, 26, 27 and 35

Notice, that the points 15 and 35 are distance from the other points and hence are outliers.

The mean of the observations including the outliers is given by
$\frac{15+23+24+26+27+35}{6} = \frac{150}{6} =25$

The mean of the observations without the outliers is given by
$\frac{23+24+26+27}{4} = \frac{100}{4} =25$

Therefore, when the outliers are removed, the mean remains the same.

3 0

3 years ago

Read 2 more answers

What is the probability that the number of “HEADs” on these four coins is equal to 3? (4 points)

slavikrds [6]

Answer:

a. $\frac{1}{4}$

Step-by-step explanation:

We are asked to find the probability of getting 3 heads on 4 flips.

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$

Since we know that flipping a fair coin has 2 equally likely possible outcomes, so flipping four coins will have $2*2*2*2=16$ possible outcomes.

Sample space of possible outcomes.

HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT,

THHH, THHT, THTH,THTT, TTHH, TTHT, TTTH, TTTT.

We can see that there are 4 favorable outcomes of getting heads.

$\text{Probability of getting 3 heads}=\frac{4}{16}$

$\text{Probability of getting 3 heads}=\frac{1}{4}$

Therefore, the probability of getting 3 heads on 4 coins will be $\frac{1}{4}$ and option a is the correct choice.

5 0

3 years ago

At a hardware store, a tool set normally costs $80. During a sale this week, the tool set costs $12 less than usual. What percen

Hoochie [10]

, $15\%$ of the usual price is the savings .

Step-by-step explanation:

Here we have , At a hardware store, a tool set normally costs $80. During a sale this week, the tool set costs $12 less than usual. We need to find What percentage of the usual price is the savings . Let's find out:

Initially we have cost as $80 , in sale it is $12 less i.e.

⇒ $80-12$