Honestly I couldn’t tell yiu
Answer:
a) The 90% confidence interval for the mean noise level at such locations
(112.46 , 163.54)
b) The critical value that should be used in constructing the confidence interval
Z₀.₁₀ = 1.645
Step-by-step explanation:
<u><em>Step(i)</em></u> :-
Noise levels at 3 airports were measured in decibels yielding the following data
108 146 160
Mean of given data

x : 108 146 160
x-x⁻ : -30 8 22
(x-x⁻ )² : 900 64 484
Variance σ ² = ∑(x-x⁻ )²/ n-1
= 
Standard deviation
σ = √724 = 26.90
<u><em>Step(ii):</em></u>-
The 90% confidence interval for the mean noise level at such locations

The critical value that should be used in constructing the confidence interval
Z₀.₁₀ = 1.645

( 138 - 25.54 , 138 + 25.54 )
(112.46 , 163.54)
Answer:
12 / 7
Step-by-step explanation:
7 ( c + d ) = 12
c + d = 12 / 7
Answer:
Step-by-step explanation:
E = V*d
1250 N/C = V*0.05 m
V = 25,000 volts
The value of the sine, cosine and tangent of the figure will be found as follows:
a] Sine
sin x=(opposite)/(hypotenuse)
opposite=7
hypotenuse=25
thus:
sin x= 7/25
b] Cosine
cos x=adjacent/hypotensue
adjacent=24
hypotenuse=25
cos x=24/25
Tangent
Tan x=opposite/adajcent
opposite=7
adjacent=24
thus
tan x=7/24