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nikklg [1K]
2 years ago
14

- 8.3 + 11.7 + x = 0 p;lssssss helppp

Mathematics
1 answer:
Ierofanga [76]2 years ago
4 0

Answer:

X = -3.4

I found that the answer should be -3.4 because I just did 11.7 - -8.3 which equals 3.4 so i just changed it so it would be a negative number.

Step-by-step explanation:

11.7 + -8.3 + -3.4

the answer is then 0 so x = -3.4

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Rudik [331]

Answer:

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2 years ago
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Joel wanted his mom to buy a super-sized box of his favorite cereal, but his mom didn't think it would fit in her cupboard. The
Lorico [155]
<h3><u>Given</u>:-</h3>

  • Volume 6,900 cm^3
  • Length = 23 cm
  • Width = 10cm

<h3><u>To Find</u>:-</h3>

  • Height of box ??

<h3><u>Solution</u>:-</h3>

\\\diamond{\underline{\underline{\sf {\;\; Calculating\; Height\;  of  \; box :-}}}}\\

\\ \pink \star \:  \: {\underline{\boxed {\bf{  Volume_{ \red{ \{Rectangle \}}}  \: = l  \times w  \times  h }}} }\; \red\bigstar  \\

Where,

  • » l denotes Length
  • » w denotes Width
  • » h denotes Height

\\  \sf \implies \: {Volume_{ \red{ \{Rectangle \}}}  \: = l  \times w  \times  h} \\

\\  \sf \implies \: { 6,900 \:   = \: 23 \:    \times  \: 10 \:   \times  h} \\

\\  \sf \implies \: { 6,900 \:   = \:  230 \:   \times \:   h} \\

\\  \sf \implies \: {  \: h  \:   = \:   \frac{6900}{230}  \:  } \\

\\  \sf \implies \: {  \: h  \:   = \:   30 \: {cm }^{3}   \:   } \\

\\ \implies{\underline{\boxed{\frak { Height = 30  \: cm^3 }}}} \; \purple\bigstar \:  \\

\\\qquad \rule{120pt}{3pt}\\

Therefore , the Volume of the Box is 30 cm ³.

5 0
2 years ago
PLEASE HELP WILL GIVE BRAINLYLIST<br> x y<br> 2 0<br> 3 1<br> 4 2<br> 5 3<br><br> y = x -
tamaranim1 [39]
I think the answer is y = x - 2
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3 0
3 years ago
let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)
statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

\sin (\theta)=\frac{3}{5}

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

x^2+3^2=5^2

Solving for x, we have

\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

\tan (y)=\frac{12}{5}

Describes the following triangle

Using the Pythagorean Theorem again, we have

5^2+12^2=h^2

Solving for h, we have

\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}

To calculate the sine and cosine of the sum

\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}

We can use the following identities

\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}

Using those identities in our problem, we're going to have

\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}

4 0
1 year ago
A+b <br> A*b<br> A-b<br> A *divide sign*<br> Which one isn't closed
blsea [12.9K]
A *divide sign* isn't closed since there isn't a second letter or number with it
5 0
3 years ago
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