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kotegsom [21]
2 years ago
13

Maria estimates college tuition and fees, room and board, books, and other charges total $10,100. She will receive a scholarship

for $1100. If she has 4 years to save, how much should she save per month to cover the costs of college (minus the scholarship)?
A.
$2525.00



B.
$2250.00



C.
$210.42



D.
$187.50
Mathematics
1 answer:
garri49 [273]2 years ago
3 0
Maria needs to save $187.50 per month in order to attend college. 

First, subtract the $1,100 scholarship from the cost of college, or $10,100, to get $9,000. This is the amount that she needs to save after 4 years. Next, since she is saving monthly, we need to know how many monthly periods are in 4 years, so multiply 12 months/year by 4 years to get 48 monthly periods. Finally, divide the total amount needed ($9,000) by the monthly periods (48) to get $187.50. This answer would change if she earned any interest on her savings, and depending on the compounding period, if any, for such interest. 
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melamori03 [73]

Answer:

A. linear

Step-by-step explanation:

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2 years ago
A recent college graduate is planning to take the first three actuarial examinations in the coming summer. She will take the fir
erica [24]

Answer:

(a) 0.7

(b) \frac 13

Step-by-step explanation:

Let E_1, E_2, and E_3 be the events of passing the 1st, 2nd, and 3rd exam individually.

Given that P(E_1)=0.9\;\cdots(i)

where P(E_1) denotes the probability of passing the 1st exam.

Condition for passing the second exam is, at first, the candidate must have to pass the 1st exam.

So, P\left(\frac{E_2}{E_1}\right)=0.8\;\cdots(ii)

where P(E_2/E_1) denotes the probability of passing the 2nd exam when she already passed the 1st exam (given, 0.8).

Similarly, as the conditional probability of passing the 3rd exam is 0.7, and the condition for this is, at first, she must have to pass the 1st and 2nd exam. i.e,

P\left(\frac{E_2}{P(E_2/E_1)}\right)=0.7\;\cdots(iii)

(a) For passing all the exams, the condition is, at first, she has to pass the 1st and 2nd exam, then she has to pass the 3rd exam too. The probability for this conditional has been given as 0.7.

So, the probability that she passes all three exams is 0.7.

(b) Given that she didn't pass all three exams that means she either failed in 1st exam or she passed the 1st and failed in 2nd exam or she passed both 1st and 2nd but failed in the 3rd exam.

Let F be the event that she didn't pass all three exams. So,

P(F)=(1-P(E_1))+\left(1-\frac{P(E_2)}{P(E_1)}\right)+\left(1-\frac{P(E_2)}{P(E_2/E_1)}}\right)

\Rightarrow P(F)=(1-0.9)+(1-0.8)+(1-0.7)=0.6

Lef F_2 be the event that she failed the 2nd exam, so

P(F_2)=1-\frac{P(E_2)}{P(E_1)}

\Rightarrow P(F_2)=1-0.8=0.2

So, the conditional probability that she failed the 2nd exam is

P\left(\frac{F_2}{F}\right)=\frac{P(F_2)}{P(F)}

\Rightarrow P\left(\frc{F_2}{F}\right)=\frac{0.2}{0.6}=\frac{1}{3}=0.33

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horrorfan [7]
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8 0
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Answer:

Step-by-step explanation:

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7 0
3 years ago
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Can someone help please?
Alekssandra [29.7K]

Answer:

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Step-by-step explanation:

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