The first term is a1 = 4 since it is given to us The common difference is d = 3. This is the value that we add to each term to get the next as the recursive steps shows when we write a(n) = a(n-1)+3 In other words, nth term = [ (n-1)st term ] + 3 next term = (previous term) + 3
Using a1 = 4 and d = 3, we get the following an = a1+d(n-1) an = 4 + 3(n-1) an = 4+3n-3 an = 3n + (4-3) an = 3n+1
