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Nana76 [90]
3 years ago
10

A recursive rule for an arithmetic sequence is a1 = 4; an = an-1 + 3 . What is an explicit rule for this sequence? (Picture atta

ched) please help? I don't remember what type of equation to use for these kinds of problems...

Mathematics
2 answers:
Slav-nsk [51]3 years ago
7 0
Answer: 3n+1
(no need to type in the "a_n" or "an" part, as it's already done)

--------------------------------------------------------------------------

Explanation:

The first term is a1 = 4 since it is given to us
The common difference is d = 3. This is the value that we add to each term to get the next as the recursive steps shows when we write a(n) = a(n-1)+3
In other words,
nth term = [ (n-1)st term ] + 3
next term = (previous term) + 3

Using a1 = 4 and d = 3, we get the following
an = a1+d(n-1)
an = 4 + 3(n-1)
an = 4+3n-3
an = 3n + (4-3)
an = 3n+1
Vlad [161]3 years ago
3 0

Answer:

a_n=4+3(n-1)

Just took the test!



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The equation for the circle below is x^2+y^2=64 what is the length of the circle’s radius
FromTheMoon [43]

Answer:

<h2>r = 8</h2>

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the equation:

x^2+y^2=64\\\\(x-0)^2+(y-0)^2=8^2

Therefore the center is (0, 0) and the radius r = 8

3 0
2 years ago
Divide the following polynomials (a4 + 4b4) ÷ (a2 - 2ab + 2b2)
telo118 [61]
(a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2+2ab+2b^2 =The answer

(a + b)^2 = a^2 + 2ab + b^2 => square of sums
(a - b)^2 = a^2 - 2ab + b^2 => square of deference
and of course one of most important ones:
a^2 - b^2 = (a - b)(a + b) => difference of squares
Best Answer: (a^4 + 4b^4) ÷ (a^2 - 2ab + 2b^2)
= [(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)] / (a^2 - 2ab + 2b^2)
= a^2 + 2ab + 2b^2
a^4 + 4b^4 => i.e. 4a^2b^2 ,
a^4 + 4a^2b^2 + 4b^4 => a^2 + 2ab + b^2 = (a + b)^2, if : a = a^2 , b = 2b^2:
(a^2 + 2b^2)^2 = a^4 + 4a^2b^2 + 4b^4 => We can't add or subtract the value to the expression.
a^4 + 4a^2b^2 + 4b^4 - 4a^2b^2 =>
(a^2 + 2b^2)^2 - 4a^2b^2 =>
(a^2 + 2b^2 - 2ab)(a^2 + 2b^2 + 2ab) =>
(a^2 - 2ab + 2b^2) (a^2 + 2ab + 2b^2)

Greetings!


8 0
3 years ago
Read 2 more answers
What is the Inverse Equation<br><br>f(x) =6x-1 ?? please I need help!​
Scrat [10]

Answer:

f^{-1}(x)=\frac{x+1}{6}

Step-by-step explanation:

So we have the function:

f(x)=6x-1

To find the inverse function, switch x and f(x), change f(x) to f⁻¹(x), and solve for f⁻¹(x). Therefore:

f(x)=6x-1

Switch:

x=6f^{-1}(x)-1

Add 1 to both sides:

x+1=6f^{-1}(x)

Divide both sides by 6:

f^{-1}(x)=\frac{x+1}{6}

And that's our answer :)

5 0
3 years ago
I need help please...
Olegator [25]

Answer:

13000 milliliters

Step-by-step explanation:

1 liter = 1000 milliliters

13 liters = 13000 milliliters

7 0
3 years ago
Read 2 more answers
If 8 is subtracted from 7 times a number the result is 34
djverab [1.8K]
7x - 8 = 34

Solving:

7x = 34 + 8
7x = 42
x = 6

Hope this helps!
5 0
3 years ago
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