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3 years ago

(-7x∧5 + 14 - 2x) + (10x∧4 + 7x + 5x∧5)

Mathematics

1 answer:

Maslowich3 years ago

7 0

$-7x^5 + 5x^5 +10x^4 -2x + 7x + 14= -2x^5 +10x^4 +5x + 14$

Your answer is $-2x^5 +10x^4 +5x + 14$

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17. Which of the following equations would graph a line parallel to 3y = x + 5? (

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The equation 3y = x + 1 would graph a line parallel to 3y = x + 5 ⇒ 1st

Step-by-step explanation:

Parallel lines have same slopes and different y-intercepts

To find which equation would graph a line parallel to 3y = x + 5

1. Put the equation in the form of y = mx + c

2. m is the slope of the line and c is the y-intercept

3. Look for the equation which has the same values of m and different

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∵ 3y = x + 5

- Divide each term of the equation by 3 to put the equation in the

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∴ y = $\frac{1}{3}$ x + $\frac{5}{3}$

∴ m = $\frac{1}{3}$

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The first answer:

∵ 3y = x + 1

- Divide each term of the equation by 3

∴ y = $\frac{1}{3}$ x + $\frac{1}{3}$

∴ m = $\frac{1}{3}$

∴ c = $\frac{1}{3}$

∵ The two equations have same slope m = $\frac{1}{3}$

∵ The two equations have different y-intercepts c = $\frac{5}{3}$

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The equation 3y = x + 1 would graph a line parallel to 3y = x + 5

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3 years ago

Find area of a parallelogram with a height of 8 inches and a base of 14 inches

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Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{112 \: {inches} \: ^{2} }}}}}$

Step-by-step explanation:

Given,

Height of a parallelogram ( h ) = 8 inches

Base of a parallelogram ( b ) = 14 inches

Area of a parallelogram ( A ) = ?

Finding the area of a parallelogram

$\boxed{ \sf{area \: of \: parallelogram \: = \: base \: \times \: height}}$

⇒ $\sf{area \: of \: parallelogram \: = \: 14 \: \times 8}$

⇒ $\sf{area \: of \: parallelogram = 112 \: {inches}^{2} }$

Hope I helped!

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