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ira [324]
2 years ago
10

Please try to help if you can.

Mathematics
1 answer:
PolarNik [594]2 years ago
7 0

The equation of the sinusoidal function is y = -2sin(x + 1.5) - 3

<h3>The sinusoidal function</h3>

The minimum and the maximum of the function are

  • Minimum = -1
  • Maximum = -5

The amplitude (A) is calculated as:

A = 0.5 * (Maximum - Minimum)

So, we have:

A = 0.5 * (-5 + 1)

A = -2

The vertical shift (d) is calculated as:

d = 0.5 * (Maximum + Minimum)

So, we have:

d = 0.5 * (-5 - 1)

d = -3

The period (P) is calculated as:

P = 2π/B

From the graph,

B = 1

So, we have:

P = 2π/1

P = 2π

So, the amplitude is -2 and the period is 2π.

<h3>The equation of the sine function</h3>

In (a), we have:

A = -2

B = 1

d = -3

A sine function is represented as:

y = A sin(Bx + C) + D

So, we have:

y = -2sin(x + C) - 3

The graph passes through the point (0, -5)

So, we have

-5 = -2sin(0 + C) - 3

Solve for C, we have

C = 1.5

So, we have:

y = -2sin(x + 1.5) - 3

Hence, the equation of the sinusoidal function is y = -2sin(x + 1.5) - 3

Read more about sinusoidal function at

brainly.com/question/10700288

#SPJ1

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Answer:

P=0.727

Step-by-step explanation:

The total coins in your pocket are 11, the probability of a nickel coming out from a random selection is \frac{4}{11}, and the probability of taking out a dime is \frac{7}{11}. In the case of the Canadian currency, you have two Canadian coins of eleven, the probability is \frac{2}{11}. The probability of select a dime or a Canadian coin is the sum of the probability of each event less the probability of  selecting the coin that is a dime and a Canadian coin:

P=\frac{7}{11}+\frac{2}{11}-\frac{1}{11}=\frac{8}{11}=0.727

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kolbaska11 [484]

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-5.5(x+1.7)+7.8(5.1-7.6x)&lt;-14.916
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-5.5a-9.35+39.78-59.28a<-14.916

-64.78a+30.43<-14.916
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