The standard form of a parabole is: (y-k) = a(x-h)², Where (h , k) are the coordinates of the vertex
In the example Vertex (3,1) ,
so (y-1) = a(x-3)². (a)
Now let's calculate a. The y-intercept coordinates(0 , 10), Replace in (a) x by 0 & y by 10:
(10-1) = a(0 - 3)²
9 = 9a and a=1
<u />The equation becomes : y-1 = (x-3)², Expand (y-1) = x²-6x+9
<u />and finally y = x² - 6x +10 (ANSWER C)
Answer:
3
Step-by-step explanation:
13144 mr brill this should help
Answer:
f(x)=x(x-5)(x+2)
Step-by-step explanation:
Since the steps of the factorization of the polynomial f(x) is not given, I will proceed to give the correct factorization of f(x).
f(x)=x³-3x²-10x
First, we factor out x since it is a common term.
f(x)=x(x²-3x-10)
Next, we factorize the quadratic expression x²-3x-10.
f(x)=x(x²-5x+2x-10)
f(x)=x(x(x-5)+2(x-5))
f(x)=x(x-5)(x+2)
The correct factorization of the polynomial f(x)=x³-3x²-10x is: f(x)=x(x-5)(x+2)
Answer:
basically multiplication, (that quantity) times 5
Step-by-step explanation:
