PLEASE HELP!!! MATH IS HORRIBLE! URGENT!!

Mathematics

2 answers:

torisob [31]3 years ago

5 0

Answer:

A. m-6/24

Step-by-step explanation:

This is the required expression because,

1. Quotient of 24 and 6 less than m.

2. It means quotient of 24 and 6 subtracted from m.

3. Representing it mathematically, m-6/24.

nevsk [136]3 years ago

4 0

Answer:

Step-by-step explanation:

The quotient of 24 and 6 :

$\frac{24}{6}$

Less than m :

$- m$

the quotient of 24 and 6 less than m :

$\frac{24}{6} - m$

Further Division :

4-m

You might be interested in

What's the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m? Round your answer to

yuradex [85]

Hello!

The Correct Answer to this would be 100%:

Option "85.4".

(Work Below)

Given:
height = 6m
chord = 20 m

We need to find the radius of the circle.

20 m = 2 √ [ 6m( 2 x radius - 6 m ) ]
20 m / 2 = 2 √[ 6m( 2 x radius - 6 m ) ] / 2
10 m = √ [ 6m( 2 x radius - 6 m ) ]
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ²
100 m² = 6 m( 2 x radius - 6 m )
100 m² = 12 m x radius - 36 sq m
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m²
136 m² = 12 m x radius
136 m² / 12 m = 12 m x radius / 12 m
<span>11.333 m = radius
</span>
the area beneath an arc:

Area = r² x arc cosine [ ( r - h ) / r ] - ( r - h ) x √( 2 x r x h - h²<span> ).
</span>
r² = (11.333 m)² = 128.444 m²
r - h= 11.333 m - 6 m = 5.333 m
r * h = 11.333 m x 6 m = 68 m²

Area = 128.444 m² x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x √[ 2 x 68 m² - 36 m² ]

Area = 128.444 m² x arc cosine [ 0.4706 ] - 5.333 m x √ [ 100m² ]

Area = 128.444 m² x 1.0808 radians - 5.333 m x 10 m

Area = 138.828 m² - 53.333 m²

Area = 85.4 m<span>²
</span>

Hope this Helps! Have A Wonderful Day! :)

And as Always...