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Anarel [89]
2 years ago
7

If a ! 0 and 5/x = (5+a) / (x+a) what is the value of x ?

Mathematics
1 answer:
gulaghasi [49]2 years ago
3 0

Answer: 5

Step-by-step explanation:

\frac{5}{x}=\frac{5+a}{x+a}\\\\5x+5a=5x+xa\\\\5a=xa\\\\x=5

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Solve this equation. 25) v - 6(4v + 6) = -82
grin007 [14]

Answer:

v = 2

Step-by-step explanation:

Hi there! I'm glad I was able to help you solve this equation!

Let's start by simplifying both sides of the equation. It's easier to solve it this way!

v - 6 (4v + 6) = -82

Distribute:

v + (-6) (4v) + (-6) (6) = -82

v + -24v + -36 = -82

Combine 'like' terms:

(v  -24v) + (-36) = -82

-23v - 36 = -82

Next, you'll want to add 36 to both sides of the equation.

-23v-36 + 36 = -82 + 36

-23v = -46

Finally, divide both sides by -23.

\frac{-23v}{-23} = \frac{-46}{-23}

v = 2

I hope this helped you! Leave a comment below if you have any further questions! :)

7 0
3 years ago
The midpoint of line MN is P(5,5). One of the end points in M(-4,2). Find the coordinate of endpoint N.
Greeley [361]
-4 + x                        2 + y
-------  =  5  and         ------  = 5
   2                               2

so x = 10 + 4 = 14  and y = 10 - 2 = 8

endpoint N = (14,8)
7 0
3 years ago
In a restaurant, the proportion of people who order coffee with their dinner is p. A simple random sample of 144 patrons of the
mote1985 [20]
<h2>Answer with explanation:</h2>

Given : In a restaurant, the proportion of people who order coffee with their dinner is p.

Sample size : n= 144

x= 120

\hat{p}=\dfrac{x}{n}=\dfrac{120}{144}=0.83333333\approx0.8333

The null and the alternative hypotheses if you want to test if p is greater than or equal to 0.85 will be :-

Null hypothesis : H_0: p\geq0.85   [ it takes equality (=, ≤, ≥) ]

Alternative hypothesis : H_1: p  [its exactly opposite of null hypothesis]

∵Alternative hypothesis is left tailed, so the test is a left tailed test.

Test statistic : z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

z=\dfrac{0.83-0.85}{\sqrt{\dfrac{0.85(1-0.85)}{144}}}\\\\=-0.561232257678\approx-0.56

Using z-vale table ,

Critical value for 0.05 significance ( left-tailed test)=-1.645

Since the calculated value of test statistic is greater than the critical value , so we failed to reject the null hypothesis.

Conclusion : We have enough evidence to support the claim that p is greater than or equal to 0.85.

8 0
3 years ago
Leena knits 10 rows in 12 minutes.
maria [59]

Answer:

It will take 30 minutes!

Hope this helps! :D

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Pls help immediately
STatiana [176]

Answer:

(3,2)

Step-by-step explanation:

5 0
4 years ago
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