From the identity:
![sec(x)= \frac{1}{cos(x)}](https://tex.z-dn.net/?f=sec%28x%29%3D%20%5Cfrac%7B1%7D%7Bcos%28x%29%7D%20)
![f(x)=sec(x)= \frac{1}{cos(x)}](https://tex.z-dn.net/?f=f%28x%29%3Dsec%28x%29%3D%20%5Cfrac%7B1%7D%7Bcos%28x%29%7D%20)
the inverse of f is g such that f(g(x))=x,
we must find g(x), such that
![\frac{1}{cos[g(x)]}=x](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bcos%5Bg%28x%29%5D%7D%3Dx%20)
thus,
![cos[g(x)]= \frac{1}{x}](https://tex.z-dn.net/?f=cos%5Bg%28x%29%5D%3D%20%5Cfrac%7B1%7D%7Bx%7D%20)
![g(x)=cos^{-1} (\frac{1}{x})](https://tex.z-dn.net/?f=g%28x%29%3Dcos%5E%7B-1%7D%20%28%5Cfrac%7B1%7D%7Bx%7D%29%20)
Answer: b. g(x)=cos^-1(1/x)
I cant see the color so i cant answer if u add the color i will answer
Answer: g(f(x)) = g(x²-7)=x
Step-by-step explanation:
Since One Radio in Davis Electronics requires 18 working resistors, then 2,145 radios will require
resistors.
Now we know that one out of 22 resistors is defective. This means that the number of non defective or perfect resistors in a set of 22 resistors is 21.
So, obviously, if we pick a set of 40,370 resistors then the set of working resistors we will get is
.
As can be clearly seen from the above calculations the required amount of working resistors is 38610 and the amount of working calculators available to us is 38535.
Thus, since the required amount of working resistors is greater than the amount of working resistors available, 40,370 resistors are not enough to assemble 2,145 radios.
I would add 24 and 36, to make 60, then I would tack on 13 and get 73.