1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alona [7]
3 years ago
11

Mr.Williams physical education class lasts 7/8 hour if instruciton is 1/5 how many minutes are not spent on instruction?

Mathematics
2 answers:
34kurt3 years ago
8 0
= 7/8 − 1/5

= ((7 × 5) − (1 × 8)) / (8 × 5)

= (35 - 8) / 40

= 27/40

= 27/40

SO, 27/40 minutes are NOT spend on instructions.

Hope I helped:P
makvit [3.9K]3 years ago
5 0

Answer

Find out the how many minutes are not spent on instruction.

To prove

Let us assume that the numbers of hours Mr. Williams is not  instruciton be x.

As given

Mr.Williams\ physical\ education\ class\ lasts\ \frac{7}{8}\ hour\ if\ instruciton\ is\ \frac{1}{5} .

Than the equation becomes

x = \frac{7}{8} - \frac{1}{5}

L.C.M of (8,5) = 40

x = \frac{7\times 5 - 1\times 8}{40}

x = \frac{35 - 8}{40}

x = \frac{27}{40}

x = \frac{27}{40}\ hours

As 1 hours = 60 mintues

Now\ convert\ \frac{27}{40}\hours\ into\ mintues.

= \frac{27\times 60}{40}

= 40.5 mintues

Therefore in 40.5 mintues Mr. Williams not spent on instruction .


You might be interested in
Pls help see the picture posted
Aleks [24]
I hope this helps you
5 0
3 years ago
A survey of 70 students from a high school is conducted. From this sample, it is found that 58 students have sent a text message
Irina-Kira [14]
Number of students who have sent a text message only is given by the difference between those that have sent a text message and those that have done both.
i.e. Number of students who has sent a text message only = 58 - 12 = 46

Number of students who have uploaded a selfie only is given by the difference between those that have uploaded a selfie and those that have done both.
i.e. Number of students who have uploaded a selfie only = 21 - 12 = 9

The total number of students surveyed is 70.
Let the number of students who have neither sent a text message nor taken a selfie today  be x, then
46 + 9 + 12 + x = 70
67 + x = 70
x = 70 - 67 = 3

Therefore, 3 students neither sent a text message nor taken a selfie today.

The number of students that have sent a text message or have taken a selfie today is given by the sum of the number of students that have sent a text message and the number of students that have taken a selfie less the number of people that have done both.
i.e. number of students that have sent a text message or have taken a selfie today = 58 + 21 - 12 = 67.
7 0
3 years ago
he box plot represents the number of minutes it takes for the students in a class to run a mile. What is the minimum of the data
Elis [28]
It's 5. Just took this test and got this question right :)
7 0
3 years ago
Read 2 more answers
Solve for X <img src="https://tex.z-dn.net/?f=5%2B7x%3D40" id="TexFormula1" title="5+7x=40" alt="5+7x=40" align="absmiddle" clas
Musya8 [376]

Answer:

x = 5

Step-by-step explanation:

To solve, first subtract 5 from each side:

5 + 7x = 40

7x = 35

Then divide each side by 7:

x = 5

5 0
2 years ago
Read 2 more answers
Show your work as you go along.
lana66690 [7]
2x+3(2x-4y)+8y-2
2x+6x-12y+8y-2
8x-12y+8y-2
8x-4y-2
8 0
3 years ago
Other questions:
  • Grand kfstusufsjshfssjg
    9·1 answer
  • X=2y-3 slope intercept form
    6·1 answer
  • 3/4 of a piece of metal has a mass of 15kg.what is the mass of 2/5 of the piece of metal
    6·1 answer
  • The correct mixed number for this fraction 11/3
    12·1 answer
  • What is 18576939*47 Thanks!!!!!
    14·2 answers
  • ??????????????????.?..
    12·1 answer
  • -X + 5+ 4x<br> simplify the expression
    10·1 answer
  • Find the value of x.<br> 9<br> 10<br> 8<br> 7
    12·1 answer
  • What does it mean to evaluate an expression in 5th grade
    15·1 answer
  • 3. The circumference of a circle is 6 pie yards.
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!