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Vlad [161]
1 year ago
10

A candy distributor needs to mix a 40% fat-content chocolate with a 60% fat-content chocolate to create 100 kilograms of a 56% f

at-content chocolate. How many kilograms of each kind of chocolate must they use?
Answer: They must mix
Kilograms of the 40% chocolate --------------------
Kilograms of the 60% chocolate --------------------
Mathematics
1 answer:
max2010maxim [7]1 year ago
8 0

Solving a system of equations we can see that:

They need to use 80kg of the 60% chocolate and 20kg of the 40% chocolate.

<h3>How to find how much of each candy needs to be used?</h3>

Let's define the variables:

  • x = kilograms of the 40% chocolate.
  • y = kilograms of the 60% chocolate.

They want to make 100kg, then:

x + y = 100

And the concentration must be of the 56%, then we can write:

x*0.4 + y*0.6 = (100)*0.56 = 56

Then we have a system of equations:

x + y = 100

x*0.4 + y*0.6 = 56

To solve this, we can isolate x on the first equation to get:

x = 100 - y

Now replace that in the other equation:

(100 - y)*0.4 + y*0.6 = 56

40 + y*0.2 = 56

y*0.2 = 16

y = 16/0.2 = 80

This means that they need to use 80kg of the 60% chocolate and the other 20kg of the 40% chocolate.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

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Five widgets and three gadgets cost $109. 90.
erma4kov [3.2K]

Answer:

one gadget costs $15.80

Step-by-step explanation:

Let w = cost of one widget

Let g = cost of one gadget

Given:

  • Five widgets and three gadgets cost $109. 90

⇒ 5w + 3g = 109.9

Given:

  • One widget and four gadgets cost $75. 70

⇒ w + 4g = 75.7

Rewrite  w + 4g = 75.7  to make w the subject:

⇒ w = 75.7 - 4g

Substitute into  5w + 3g = 109.9  and solve for g:

⇒ 5(75.7 - 4g) + 3g = 109.9

⇒ 378.5 - 20g + 3g = 109.9

⇒ 378.5 - 109.9 = 20g - 3g

⇒ 268.6 = 17g

⇒ g = 15.8

Therefore, one gadget costs $15.80

To find the cost of one widget, substitute the found value for g into
w = 75.7 - 4g and solve for w:

⇒ w = 75.7 - 4(15.8)

⇒ w = 75.7 - 63.2

⇒ w = 12.5

Therefore, one widget costs $12.50

5 0
2 years ago
How do I do this problem ?
NeTakaya
5÷3=1.66
1.66×8=13.28, round to 13.3
8 0
3 years ago
Read 2 more answers
Which of the following expression(s) are fourth-degree trinomials? Select all that apply.
DaniilM [7]

Answer:

Options A and B are polynomial of the fourth degree

Step-by-step explanation:

In this problem, option

A. 3x2y + 5x3y + 6y4

Is a Polynomial of the fourth degree because of the 6y⁴ term which is the highest degree

Also the option

B. 6y4 + 5x3 + 1 has a 6y⁴ term which indicates that the polynomial is a fourth degree polynomial

What is the degree of a polynomial?

In mathematics, the degree of a polynomial is the highest of the degrees of the polynomial's monomials with non-zero coefficients. The degree of a term is the sum of the exponents of the variables that appear in it, and thus is a non-negative integer

5 0
2 years ago
Nadia cuts 3 pieces pf equal length from 8 yards of ribbon. How long is each piece?
Harman [31]
Its 8 divided by 3 which equals 2.6
5 0
3 years ago
S
pogonyaev

Answer:

x=71 and y=19

Step-by-step explanation:

First, we write out the first sentence as an equation. This is x+y=90. We also know that x=3y+14 because of the second sentence. Using this, we can substitute x in the first equation with what it is (3y+14). This makes the new equation 3y+14+y=90. Then, we collect like terms by adding the 'y's together - making 4y+14=90. We need to make the letters on one side and the numbers on the other. To do this, we subtract 14 from each side, making 4y=76. We want to find out what 'y' is by itself (not multiplied by four) so we divide each side by 4. This means that we have found out that y=19 because 76÷4=19. Now, it is time to solve x. Using our new knowledge that y=19, we can replace y in the equation x+y=90 with 19 so now we have x+19=90. This is the same as 90-19=x and we know that 90-19=71, so x must be 71. In conclusion, x=71 and y=19.

I hope this helps, have a great day!

8 0
3 years ago
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