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Vlad [161]
1 year ago
10

A candy distributor needs to mix a 40% fat-content chocolate with a 60% fat-content chocolate to create 100 kilograms of a 56% f

at-content chocolate. How many kilograms of each kind of chocolate must they use?
Answer: They must mix
Kilograms of the 40% chocolate --------------------
Kilograms of the 60% chocolate --------------------
Mathematics
1 answer:
max2010maxim [7]1 year ago
8 0

Solving a system of equations we can see that:

They need to use 80kg of the 60% chocolate and 20kg of the 40% chocolate.

<h3>How to find how much of each candy needs to be used?</h3>

Let's define the variables:

  • x = kilograms of the 40% chocolate.
  • y = kilograms of the 60% chocolate.

They want to make 100kg, then:

x + y = 100

And the concentration must be of the 56%, then we can write:

x*0.4 + y*0.6 = (100)*0.56 = 56

Then we have a system of equations:

x + y = 100

x*0.4 + y*0.6 = 56

To solve this, we can isolate x on the first equation to get:

x = 100 - y

Now replace that in the other equation:

(100 - y)*0.4 + y*0.6 = 56

40 + y*0.2 = 56

y*0.2 = 16

y = 16/0.2 = 80

This means that they need to use 80kg of the 60% chocolate and the other 20kg of the 40% chocolate.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

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Alona [7]

Answer:

c. m∠1 + m∠6 = m∠4 + m∠6

Step-by-step explanation:

Given: The lines l and m are parallel lines.

The parallel lines cut two transverse lines. Here we can use the properties of transverse and find the incorrect statements.

a.  m∠1 + m∠2 = m∠3 + m∠4

Here m∠1 and m∠2 are supplementary angles add upto 180 degrees.

m∠3 and  m∠4 are supplementary angles add upto 180 degrees.

Therefore, the statement is true.

b. m∠1 + m∠5 = m∠3 + m∠4

m∠1 + m∠5 = 180 same side of the adjacent angles.

m∠3 + m∠4 = 180, supplementary angles add upto 180 degrees.

Therefore, the statement is true.

Now let's check c.

m∠1 + m∠6 = m∠4 + m∠6

We can cancel out m∠6, we get

m∠1 = m∠4 which  is not true

Now let's check d.

m∠3 + m∠4 = m∠7 + m∠4

We can cancel out m∠4, we get

m∠3 = m∠7, alternative interior angles are equal.

It is true.

Therefore, answer is c. m∠1 + m∠6 = m∠4 + m∠6

3 0
3 years ago
What is the period of y = 8 cos (5pie x + 3pie/2)-9<br> Give an exact value. Units
zzz [600]

\\ \rm\Rrightarrow y=Acos(Bx+C)+D

  • This is the general formula and the period is 2π/B

Now our given function

\\ \rm\Rrightarrow y=8cos\left(5\pi x+\dfrac{3\pi}{2}\right)-9

On comparing we get

  • A=8
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  • C=3π/2
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Period:-

\\ \rm\Rrightarrow \dfrac{2\pi}{B}

\\ \rm\Rrightarrow \dfrac{2\pi}{5\pi}

\\ \rm\Rrightarrow \dfrac{2}{5}

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2 years ago
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astra-53 [7]

Answer:

Step-by-step explanation:

\Large \boldsymbol{} f(x)  \ \ inverse  \ \  function    \ \ (f(x))^{-1} \\\\ y=7x+5 \\\\x=7y+5 \\\\ y=\dfrac{x-5}{7}  \ \  or \  \  f(x)^{-1}= \dfrac{x-5}{7}

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Answer:

1

Step-by-step explanation:

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