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Vlad [161]
1 year ago
10

A candy distributor needs to mix a 40% fat-content chocolate with a 60% fat-content chocolate to create 100 kilograms of a 56% f

at-content chocolate. How many kilograms of each kind of chocolate must they use?
Answer: They must mix
Kilograms of the 40% chocolate --------------------
Kilograms of the 60% chocolate --------------------
Mathematics
1 answer:
max2010maxim [7]1 year ago
8 0

Solving a system of equations we can see that:

They need to use 80kg of the 60% chocolate and 20kg of the 40% chocolate.

<h3>How to find how much of each candy needs to be used?</h3>

Let's define the variables:

  • x = kilograms of the 40% chocolate.
  • y = kilograms of the 60% chocolate.

They want to make 100kg, then:

x + y = 100

And the concentration must be of the 56%, then we can write:

x*0.4 + y*0.6 = (100)*0.56 = 56

Then we have a system of equations:

x + y = 100

x*0.4 + y*0.6 = 56

To solve this, we can isolate x on the first equation to get:

x = 100 - y

Now replace that in the other equation:

(100 - y)*0.4 + y*0.6 = 56

40 + y*0.2 = 56

y*0.2 = 16

y = 16/0.2 = 80

This means that they need to use 80kg of the 60% chocolate and the other 20kg of the 40% chocolate.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

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(n\div{3})-5={-7}

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Step-by-step explanation:

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*Mastery Check. DO NOT ask for help. Find the area of the sector. Round your answer to the nearest tenth.
Juliette [100K]

The area of the sector is 472.6 ft²

<h3>Area of a Sector</h3>

For finding the area of the sector, you need apply the formula:

A=\pi r^2* \frac{\alpha }{360}, where:

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α= central angle

The question gives:

r= radius= 19 ft

α= central angle = 150°

Thus, the area of the sector will be:

A=\pi r^2* \frac{\alpha }{360}=\pi *19^2*\frac{150}{360} =472.6

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brainly.com/question/22972014

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3 0
2 years ago
17) Find the surface area of the right triangular prism shown below:<br> 5<br> 2<br> 5/2<br> 3/2
harkovskaia [24]

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D

Step-by-step explanation:

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7 0
3 years ago
Let f(x) represent a function.
STatiana [176]

Answer:

For f(x+\frac{5}{4}), f(x) is translated \frac{5}{4} units left.

For f(x)-\frac{5}{4}, f(x) is translated \frac{5}{4} units down.

Step-by-step explanation:

The transformation of f(x)\rightarrow f(x+C) means that the graph shift to left by C units if C is positive number and shifts to right by C units if C is a negative number.

The transformation of f(x)\rightarrow f(x)+C means that the graph shifts up by C units if C is positive number and shifts down by C units if C is a negative number.

Here, in the transformation of f(x)\rightarrow f(x+\frac{5}{4}),C = \frac{5}{4}>0, so, the function translates left by \frac{5}{4} units.

Similarly, in the transformation of f(x)\rightarrow f(x)-\frac{5}{4},C = -\frac{5}{4}, so, the function translates down by \frac{5}{4} units.

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3 years ago
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