Solving a system of equations we can see that:
They need to use 80kg of the 60% chocolate and 20kg of the 40% chocolate.
<h3>
How to find how much of each candy needs to be used?</h3>
Let's define the variables:
- x = kilograms of the 40% chocolate.
- y = kilograms of the 60% chocolate.
They want to make 100kg, then:
x + y = 100
And the concentration must be of the 56%, then we can write:
x*0.4 + y*0.6 = (100)*0.56 = 56
Then we have a system of equations:
x + y = 100
x*0.4 + y*0.6 = 56
To solve this, we can isolate x on the first equation to get:
x = 100 - y
Now replace that in the other equation:
(100 - y)*0.4 + y*0.6 = 56
40 + y*0.2 = 56
y*0.2 = 16
y = 16/0.2 = 80
This means that they need to use 80kg of the 60% chocolate and the other 20kg of the 40% chocolate.
If you want to learn more about systems of equations:
brainly.com/question/13729904
#SPJ1
