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Illusion [34]
1 year ago
7

Select the correct answer. what is the variable being tested in an experiment? a. placebo b. response variable c. control variab

le d. explanatory variable
Mathematics
2 answers:
Darya [45]1 year ago
4 0

The variable being tested in an experiment is the (b) response variable

<h3>How to determine the variable name?</h3>

The statement is given as:

<em>what is the variable being tested in an experiment?</em>

As a general rule, the variable being tested in an experiment is referred to as the dependent variable

The dependent variable is represented with y and it is also known as the response variable

Hence, the variable being tested in an experiment is the (b) response variable

Read more about response variable at

brainly.com/question/14662435

#SPJ1

Step2247 [10]1 year ago
4 0

Answer:

explanatory variable

Step-by-step explanation:

plato 2022

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amm1812

Answer:

r = 44

Step-by-step explanation:

12 = r - (34 - 2)

Solve for r

___________

To solve, we need to isolate r.

Distribute the negative sign with the numbers within the parenthesis :

12 = r - 34 + 2

Add like terms :

12 = r - 32

Add 32 to both sides :

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Answer:

(a) The mean or expected value of <em>X </em>is 2.2.

(b) The standard deviation of <em>X</em> is 1.3.

Step-by-step explanation:

Let <em>X</em> = number of times the traffic light is red when a commuter passes through the traffic lights.

The probability distribution of <em>X</em> id provided.

The formula to compute the mean or expected value of <em>X </em>is:

\mu=E(X)=\sum x.P(X=x)

The formula to compute the standard deviation of <em>X </em>is:

\sigma=\sqrt{E(X^{2})-(E(X))^{2}}

The formula of E (X²) is:

E(X^{2})=\sum x^{2}.P(X=x)

(a)

Compute the expected value of <em>X</em> as follows:

E(X)=\sum x.P(X=x)\\=(0\times0.06)+(1\times0.25)+(2\times0.35)+(3\times0.15)+(4\times0.13)+(5\times0.06)\\=2.22\\\approx2.2

Thus, the mean or expected value of <em>X </em>is 2.2.

(b)

Compute the value of E (X²) as follows:

E(X^{2})=\sum x^{2}.P(X=x)\\=(0^{2}\times0.06)+(1^{2}\times0.25)+(2^{2}\times0.35)+(3^{2}\times0.15)+(4^{2}\times0.13)+(5^{2}\times0.06)\\=6.58

Compute the standard deviation of <em>X</em> as follows:

\sigma=\sqrt{E(X^{2})-(E(X))^{2}}\\=\sqrt{6.58-(2.22)^{2}}\\=\sqrt{1.6516}\\=1.285\\\approx1.3

Thus, the standard deviation of <em>X</em> is 1.3.

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