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ozzi
1 year ago
13

State the coordinates of the point.

Mathematics
1 answer:
Reptile [31]1 year ago
8 0
From the given graph ,

The coordinates of the point is ,

-10 is marked on x-axis and on y-axis it is 0

Hence the ordered pair/coordinates are as follows : \(-10,0)
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-4 + 4 <br> Same signs? <br> Different sign?<br> Add/Subtract?
marin [14]

Answer:

Step-by-step explanation:

-4 is negative 4 witch is less then 4. -4 +4 =0

4 0
3 years ago
Read 2 more answers
Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

5 0
3 years ago
Sam spent $16 on a large pizza and two drinks. If the pizza was 75% of the cost, how much did each drink cost?
Veseljchak [2.6K]

Each drink costs $2.

7 0
3 years ago
After flying between two black holes, our engines have been a bit janky. The probability of one of any of our 8 power couplings
otez555 [7]

Answer:

Step-by-step explanation:

We would apply the formula for binomial distribution. It is expressed as

P(x = r) = nCr × q^(n - r) × p^r

Where

p represents probability of success

q represents probability of failure.

n represents number of sample.

From the information given,

p = 10% = 10/100 = 0.1

q = 1 - q = 1 - 0.1 = 0.9

n = 8

1)The probability that none fails is

P(x = 0) = 8C0 × 0.9^(8 - 0) × 0.1^0

P(x = 0) = 0.43

2) The probability that one fails is

P(x = 1) = 8C1 × 0.9^(8 - 1) × 0.1^1

P(x = 1) = 0.38

3) The probability that four fails is

P(x = 4) = 8C4 × 0.9^(8 - 4) × 0.1^4

P(x = 4) = 0.0046

3) The probability that six fails is

P(x = 6) = 8C6 × 0.9^(8 - 6) × 0.1^6

P(x = 6) = 0.00002268

4) The probability that eight fails is

P(x = 8) = 8C8 × 0.1^(8 - 8) × 0.1^8

P(x = 8) = 0.00000001

5 0
3 years ago
Simplify 9x + 4y -4y -3x +5y
irinina [24]
9x+2y

Hope that helps :)
5 0
3 years ago
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